Answered

Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Connect with professionals on our platform to receive accurate answers to your questions quickly and efficiently. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

Samples are to be collected at four times during the day to create a 500-milliliter composite sample for COD analysis. The plant flow data are shown below. From the data given, calculate the volume of the discrete (grab) sample to be collected at 1800.

\begin{tabular}{|c|c|}
\hline
Time & Flow (Q), MGD \\
\hline
0000 / 2400 & 1 \\
\hline
0600 & 5 \\
\hline
1200 & 4 \\
\hline
1800 & 2 \\
\hline
\end{tabular}


Sagot :

To determine the volume of the discrete (grab) sample to be collected at 1800 for a 500 milliliter composite sample for COD analysis, we need to follow these steps:

1. Identify the Flow Rates at Each Time Interval:
- 0000/2400 hours: 1 million gallons per day (MGD)
- 0600 hours: 5 MGD
- 1200 hours: 4 MGD
- 1800 hours: 2 MGD

2. Calculate the Total Flow Over the Day:
- Sum the flow rates at each time interval:
[tex]\[ 1 \text{ MGD} + 5 \text{ MGD} + 4 \text{ MGD} + 2 \text{ MGD} \][/tex]
[tex]\[ = 12 \text{ MGD} \][/tex]

3. Understand the Total Composite Sample Volume:
- We are given that the total composite sample volume to be created is 500 milliliters.

4. Determine the Proportion of Flow at 1800 Hours Relative to the Total Flow:
- The flow rate at 1800 hours is 2 MGD.
- The total flow over the day is 12 MGD.

5. Calculate the Volume of the Grab Sample to be Collected at 1800:
- The volume of the grab sample to be collected is proportional to the flow rate at 1800 hours. To find this, use the fractional share of the 1800 flow relative to the total flow and multiply by the total composite volume:
[tex]\[ \text{Grab Sample Volume} = \left(\frac{\text{Flow at 1800}}{\text{Total Flow}}\right) \times \text{Total Composite Volume} \][/tex]
[tex]\[ = \left(\frac{2 \text{ MGD}}{12 \text{ MGD}}\right) \times 500 \text{ milliliters} \][/tex]
[tex]\[ = \left(\frac{2}{12}\right) \times 500 \text{ milliliters} \][/tex]
[tex]\[ = \left(\frac{1}{6}\right) \times 500 \text{ milliliters} \][/tex]
[tex]\[ = 83.33 \text{ milliliters} \][/tex]

So, the volume of the discrete (grab) sample to be collected at 1800 is 83.33 milliliters.
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.