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[tex]$\triangle RST \sim \triangle RYX$[/tex] by the SSS similarity theorem.

Which ratio is also equal to [tex]$\frac{RT}{RX}$[/tex] and [tex]$\frac{RS}{RY}$[/tex]?

A. [tex]$\frac{XY}{TS}$[/tex]

B. [tex]$\frac{SY}{RY}$[/tex]

C. [tex]$\frac{RX}{XT}$[/tex]

D. [tex]$\frac{ST}{YX}$[/tex]


Sagot :

Given that [tex]\(\triangle RST \sim \triangle RYX\)[/tex] by the SSS (Side-Side-Side) similarity theorem, the corresponding sides of similar triangles are proportional. Let's identify the corresponding sides in these similar triangles:

- [tex]\(RT\)[/tex] in [tex]\(\triangle RST\)[/tex] corresponds to [tex]\(RX\)[/tex] in [tex]\(\triangle RYX\)[/tex]
- [tex]\(RS\)[/tex] in [tex]\(\triangle RST\)[/tex] corresponds to [tex]\(RY\)[/tex] in [tex]\(\triangle RYX\)[/tex]
- [tex]\(ST\)[/tex] in [tex]\(\triangle RST\)[/tex] corresponds to [tex]\(YX\)[/tex] in [tex]\(\triangle RYX\)[/tex]

Given this proportionality, we can write the following ratios between corresponding sides:

- [tex]\(\frac{RT}{RX} = \frac{RS}{RY}\)[/tex]
- [tex]\(\frac{RS}{RY} = \frac{ST}{YX}\)[/tex]

Thus, all three ratios [tex]\(\frac{RT}{RX}\)[/tex], [tex]\(\frac{RS}{RY}\)[/tex], and [tex]\(\frac{ST}{YX}\)[/tex] are equal. The question asks which ratio among the given options is also equal to [tex]\(\frac{RT}{RX}\)[/tex] and [tex]\(\frac{RS}{RY}\)[/tex].

From our analysis, we see that the ratio [tex]\(\frac{ST}{YX}\)[/tex] is equal to these ratios because:

[tex]\[ \frac{RT}{RX} = \frac{RS}{RY} = \frac{ST}{YX} \][/tex]

Therefore, the ratio [tex]\(\frac{ST}{YX}\)[/tex] is the one that is also equal to [tex]\(\frac{RT}{RX}\)[/tex] and [tex]\(\frac{RS}{RY}\)[/tex].

Hence, the correct answer is:

[tex]\(\frac{ST}{YX}\)[/tex]