At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Get immediate and reliable answers to your questions from a community of experienced professionals on our platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
Given the reaction:
[tex]\[ \text{H}_{2}(g) + \text{I}_{2}(g) \leftrightarrow 2 \text{HI}(g) \][/tex]
The equilibrium constant expression [tex]\( K_p \)[/tex] is related to the partial pressures of the gases involved. For the general reaction:
[tex]\[ aA + bB \leftrightarrow cC + dD \][/tex]
The equilibrium constant [tex]\( K_p \)[/tex] is expressed as:
[tex]\[ K_p = \frac{(P_C)^c (P_D)^d}{(P_A)^a (P_B)^b} \][/tex]
For the given reaction, the equilibrium constant expression [tex]\( K_p \)[/tex] will be:
[tex]\[ K_p = \frac{(P_{\text{HI}})^2}{(P_{\text{H}_2})(P_{\text{I}_2})} \][/tex]
Interpreting the given options:
- Option A: [tex]\( K_p = \frac{1}{P_{\text{H}_2} P_{\text{I}_2}} \)[/tex] (Incorrect)
- Option B: [tex]\( K_p = \frac{(P_{\text{HI}})^2}{(P_{\text{H}_2})(P_{\text{I}_2})} \)[/tex] (Correct)
- Option C: [tex]\( K_p = \frac{P_{\text{H}_2} P_{\text{I}_2}}{(P_{\text{HI}})^2} \)[/tex] (Incorrect)
- Option D: [tex]\( K_p = P_{\text{H}_2} P_{\text{I}_2} \)[/tex] (Incorrect)
Thus, the correct expression for [tex]\( K_p \)[/tex] is:
[tex]\[ \boxed{B. \; K_p = \frac{(P_{\text{HI}})^2}{(P_{\text{H}_2})(P_{\text{I}_2})}} \][/tex]
For a reaction to shift towards the product direction, the reaction quotient [tex]\( Q \)[/tex] needs to be compared to the equilibrium constant [tex]\( K \)[/tex]. The reaction quotient [tex]\( Q \)[/tex] is given by:
[tex]\[ Q_c = \frac{[\text{products}]}{[\text{reactants}]} \][/tex]
For the reaction to proceed towards the products' direction:
[tex]\[ Q_c < K_c \][/tex]
Interpreting the given options:
- Option a: [tex]\( Q_c = K_c = 0 \)[/tex] (Not logical, both cannot be zero)
- Option B: [tex]\( Q_c < K_c \)[/tex] (Correct)
- Option C: [tex]\( Q_c > K_c \)[/tex] (Incorrect, would shift towards reactants)
- Option D: [tex]\( Q_c = K_c \)[/tex] (Indicates equilibrium, no shift)
Therefore, for a reaction to shift towards the product direction, the correct condition is:
[tex]\[ \boxed{B. \; Q_c < K_c} \][/tex]
[tex]\[ \text{H}_{2}(g) + \text{I}_{2}(g) \leftrightarrow 2 \text{HI}(g) \][/tex]
The equilibrium constant expression [tex]\( K_p \)[/tex] is related to the partial pressures of the gases involved. For the general reaction:
[tex]\[ aA + bB \leftrightarrow cC + dD \][/tex]
The equilibrium constant [tex]\( K_p \)[/tex] is expressed as:
[tex]\[ K_p = \frac{(P_C)^c (P_D)^d}{(P_A)^a (P_B)^b} \][/tex]
For the given reaction, the equilibrium constant expression [tex]\( K_p \)[/tex] will be:
[tex]\[ K_p = \frac{(P_{\text{HI}})^2}{(P_{\text{H}_2})(P_{\text{I}_2})} \][/tex]
Interpreting the given options:
- Option A: [tex]\( K_p = \frac{1}{P_{\text{H}_2} P_{\text{I}_2}} \)[/tex] (Incorrect)
- Option B: [tex]\( K_p = \frac{(P_{\text{HI}})^2}{(P_{\text{H}_2})(P_{\text{I}_2})} \)[/tex] (Correct)
- Option C: [tex]\( K_p = \frac{P_{\text{H}_2} P_{\text{I}_2}}{(P_{\text{HI}})^2} \)[/tex] (Incorrect)
- Option D: [tex]\( K_p = P_{\text{H}_2} P_{\text{I}_2} \)[/tex] (Incorrect)
Thus, the correct expression for [tex]\( K_p \)[/tex] is:
[tex]\[ \boxed{B. \; K_p = \frac{(P_{\text{HI}})^2}{(P_{\text{H}_2})(P_{\text{I}_2})}} \][/tex]
For a reaction to shift towards the product direction, the reaction quotient [tex]\( Q \)[/tex] needs to be compared to the equilibrium constant [tex]\( K \)[/tex]. The reaction quotient [tex]\( Q \)[/tex] is given by:
[tex]\[ Q_c = \frac{[\text{products}]}{[\text{reactants}]} \][/tex]
For the reaction to proceed towards the products' direction:
[tex]\[ Q_c < K_c \][/tex]
Interpreting the given options:
- Option a: [tex]\( Q_c = K_c = 0 \)[/tex] (Not logical, both cannot be zero)
- Option B: [tex]\( Q_c < K_c \)[/tex] (Correct)
- Option C: [tex]\( Q_c > K_c \)[/tex] (Incorrect, would shift towards reactants)
- Option D: [tex]\( Q_c = K_c \)[/tex] (Indicates equilibrium, no shift)
Therefore, for a reaction to shift towards the product direction, the correct condition is:
[tex]\[ \boxed{B. \; Q_c < K_c} \][/tex]
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.