Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
To find the molarity of the solution, follow these steps:
1. Convert the volume from milliliters to liters:
- We know that 1,000 milliliters is equivalent to 1 liter.
- So, the volume of the solution in liters is:
[tex]\[ \frac{2300 \text{ milliliters}}{1000} = 2.3 \text{ liters} \][/tex]
2. Determine the molar mass of calcium nitrate [tex]\(\text{Ca(NO}_3\text{)}_2\)[/tex]:
- The atomic masses of the elements are:
- Calcium (Ca): [tex]\(40.08 \text{ g/mol}\)[/tex]
- Nitrogen (N): [tex]\(14.01 \text{ g/mol}\)[/tex] per atom
- Oxygen (O): [tex]\(16.00 \text{ g/mol}\)[/tex] per atom
- Calcium nitrate contains:
- 1 calcium atom
- 2 nitrogen atoms
- 6 oxygen atoms
- Therefore, the molar mass is calculated as:
[tex]\[ 40.08 + (2 \times 14.01) + (6 \times 16.00) = 40.08 + 28.02 + 96.00 = 164.1 \text{ g/mol} \][/tex]
3. Calculate the number of moles of calcium nitrate:
- Using the formula:
[tex]\[ \text{moles} = \frac{\text{mass}}{\text{molar mass}} \][/tex]
- For the given mass of 127 grams:
[tex]\[ \text{moles} = \frac{127 \text{ grams}}{164.1 \text{ g/mol}} = 0.7739183424741012 \text{ moles} \][/tex]
4. Determine the molarity of the solution:
- Molarity is defined as the number of moles of solute per liter of solution:
[tex]\[ \text{Molarity} = \frac{\text{moles of solute}}{\text{volume of solution in liters}} \][/tex]
- Substituting the values:
[tex]\[ \text{Molarity} = \frac{0.7739183424741012 \text{ moles}}{2.3 \text{ liters}} = 0.33605841 \text{ M} \][/tex]
5. Round the final answer to two significant figures:
[tex]\[ \text{Molarity} \approx 0.34 \text{ M} \][/tex]
The molarity of the solution is [tex]\(0.34\)[/tex] M.
1. Convert the volume from milliliters to liters:
- We know that 1,000 milliliters is equivalent to 1 liter.
- So, the volume of the solution in liters is:
[tex]\[ \frac{2300 \text{ milliliters}}{1000} = 2.3 \text{ liters} \][/tex]
2. Determine the molar mass of calcium nitrate [tex]\(\text{Ca(NO}_3\text{)}_2\)[/tex]:
- The atomic masses of the elements are:
- Calcium (Ca): [tex]\(40.08 \text{ g/mol}\)[/tex]
- Nitrogen (N): [tex]\(14.01 \text{ g/mol}\)[/tex] per atom
- Oxygen (O): [tex]\(16.00 \text{ g/mol}\)[/tex] per atom
- Calcium nitrate contains:
- 1 calcium atom
- 2 nitrogen atoms
- 6 oxygen atoms
- Therefore, the molar mass is calculated as:
[tex]\[ 40.08 + (2 \times 14.01) + (6 \times 16.00) = 40.08 + 28.02 + 96.00 = 164.1 \text{ g/mol} \][/tex]
3. Calculate the number of moles of calcium nitrate:
- Using the formula:
[tex]\[ \text{moles} = \frac{\text{mass}}{\text{molar mass}} \][/tex]
- For the given mass of 127 grams:
[tex]\[ \text{moles} = \frac{127 \text{ grams}}{164.1 \text{ g/mol}} = 0.7739183424741012 \text{ moles} \][/tex]
4. Determine the molarity of the solution:
- Molarity is defined as the number of moles of solute per liter of solution:
[tex]\[ \text{Molarity} = \frac{\text{moles of solute}}{\text{volume of solution in liters}} \][/tex]
- Substituting the values:
[tex]\[ \text{Molarity} = \frac{0.7739183424741012 \text{ moles}}{2.3 \text{ liters}} = 0.33605841 \text{ M} \][/tex]
5. Round the final answer to two significant figures:
[tex]\[ \text{Molarity} \approx 0.34 \text{ M} \][/tex]
The molarity of the solution is [tex]\(0.34\)[/tex] M.
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.