Westonci.ca connects you with experts who provide insightful answers to your questions. Join us today and start learning! Connect with a community of experts ready to help you find accurate solutions to your questions quickly and efficiently. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
To solve the equation [tex]\( \frac{1}{c-3} - \frac{1}{c} = \frac{3}{c(c-3)} \)[/tex], let's proceed step by step:
1. Identify the common denominator:
The common denominator of the fractions on both sides of the equation is [tex]\( c(c-3) \)[/tex].
2. Express each term with the common denominator:
[tex]\[ \frac{1}{c-3} = \frac{c}{c(c-3)}, \quad \frac{1}{c} = \frac{c-3}{c(c-3)} \][/tex]
3. Rewriting the equation with a common denominator:
[tex]\[ \frac{c}{c(c-3)} - \frac{c-3}{c(c-3)} = \frac{3}{c(c-3)} \][/tex]
4. Combine the fractions on the left side:
[tex]\[ \frac{c - (c-3)}{c(c-3)} = \frac{3}{c(c-3)} \][/tex]
5. Simplify the numerator on the left:
[tex]\[ \frac{c - c + 3}{c(c-3)} = \frac{3}{c(c-3)} \][/tex]
[tex]\[ \frac{3}{c(c-3)} = \frac{3}{c(c-3)} \][/tex]
6. Since both sides of the equation are equal:
This identity confirms that the equation holds true generally for [tex]\( c \)[/tex] except where the denominators are undefined, i.e., where [tex]\( c \)[/tex] causes division by zero.
7. Determine the values that make the denominators zero:
[tex]\[ c(c-3) \neq 0 \][/tex]
[tex]\[ c \neq 0 \quad \text{and} \quad c \neq 3 \][/tex]
8. Conclude that the equation has no solutions at [tex]\( c=0 \)[/tex] and [tex]\( c=3 \)[/tex]:
Since the integers [tex]\( c = 0 \)[/tex] and [tex]\( c = 3 \)[/tex] would cause division by zero, these values are not valid solutions.
Therefore, the solution to the equation [tex]\( \frac{1}{c-3} - \frac{1}{c} = \frac{3}{c(c-3)} \)[/tex] is:
[tex]\[ \text{No solution} \][/tex]
1. Identify the common denominator:
The common denominator of the fractions on both sides of the equation is [tex]\( c(c-3) \)[/tex].
2. Express each term with the common denominator:
[tex]\[ \frac{1}{c-3} = \frac{c}{c(c-3)}, \quad \frac{1}{c} = \frac{c-3}{c(c-3)} \][/tex]
3. Rewriting the equation with a common denominator:
[tex]\[ \frac{c}{c(c-3)} - \frac{c-3}{c(c-3)} = \frac{3}{c(c-3)} \][/tex]
4. Combine the fractions on the left side:
[tex]\[ \frac{c - (c-3)}{c(c-3)} = \frac{3}{c(c-3)} \][/tex]
5. Simplify the numerator on the left:
[tex]\[ \frac{c - c + 3}{c(c-3)} = \frac{3}{c(c-3)} \][/tex]
[tex]\[ \frac{3}{c(c-3)} = \frac{3}{c(c-3)} \][/tex]
6. Since both sides of the equation are equal:
This identity confirms that the equation holds true generally for [tex]\( c \)[/tex] except where the denominators are undefined, i.e., where [tex]\( c \)[/tex] causes division by zero.
7. Determine the values that make the denominators zero:
[tex]\[ c(c-3) \neq 0 \][/tex]
[tex]\[ c \neq 0 \quad \text{and} \quad c \neq 3 \][/tex]
8. Conclude that the equation has no solutions at [tex]\( c=0 \)[/tex] and [tex]\( c=3 \)[/tex]:
Since the integers [tex]\( c = 0 \)[/tex] and [tex]\( c = 3 \)[/tex] would cause division by zero, these values are not valid solutions.
Therefore, the solution to the equation [tex]\( \frac{1}{c-3} - \frac{1}{c} = \frac{3}{c(c-3)} \)[/tex] is:
[tex]\[ \text{No solution} \][/tex]
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.