Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Get quick and reliable solutions to your questions from a community of experienced experts on our platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

Explain why the given function is not a polynomial function.

[tex]f(x)=x^3+3|x|-5[/tex]

Choose the correct answer below.
A. The function is not a polynomial function because of the presence of a negative constant.
B. The function is not a polynomial function because the leading coefficient is 1.
C. The function is not a polynomial function because of the presence of [tex]|x|[/tex].
D. The function is not a polynomial function because the graph is not a continuous curve.


Sagot :

To determine why [tex]\( f(x) = x^3 + 3|x| - 5 \)[/tex] is not a polynomial function, we need to understand the definition of a polynomial function.

A polynomial function is a mathematical expression involving a sum of powers of the variable [tex]\( x \)[/tex], with non-negative integer exponents, multiplied by coefficients which are real numbers. The general form of a polynomial function is:
[tex]\[ P(x) = a_n x^n + a_{n-1} x^{n-1} + \ldots + a_1 x + a_0 \][/tex]
where [tex]\( a_n, a_{n-1}, \ldots, a_1, a_0 \)[/tex] are constants (real numbers), and [tex]\( n \)[/tex] is a non-negative integer.

Now, let's analyze the given function [tex]\( f(x) = x^3 + 3|x| - 5 \)[/tex]:
- The term [tex]\( x^3 \)[/tex] is a polynomial term because it follows the form [tex]\( x^n \)[/tex] with [tex]\( n \)[/tex] being a non-negative integer (in this case, [tex]\( n = 3 \)[/tex]).
- The term [tex]\( -5 \)[/tex] is also a polynomial term, because constants are considered valid polynomial terms with [tex]\( n = 0 \)[/tex] (i.e., [tex]\( x^0 = 1 \)[/tex]).
- The term [tex]\( 3|x| \)[/tex] involves the absolute value of [tex]\( x \)[/tex], which is not of the form [tex]\( x^n \)[/tex] for any non-negative integer [tex]\( n \)[/tex].

The presence of the absolute value [tex]\( |x| \)[/tex] makes the function [tex]\( f(x) \)[/tex] not a polynomial function because the absolute value term does not fit into the standard definition of a polynomial term. Polynomial functions do not include absolute values, square roots, or other non-polynomial operations on [tex]\( x \)[/tex].

Therefore, the correct answer is:
C. The function is not a polynomial function because of the presence of [tex]\( |x| \)[/tex].