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Evaluate the integral:
[tex]\[ \int 2bx^3 \, dx \][/tex]

Sagot :

GinnyAnswer
To solve the integral [tex]\(\int 2bx^3 \, dx\)[/tex], we follow a series of steps to find the antiderivative.

1. Identify the integrand:
The integrand is [tex]\(2bx^3\)[/tex], where [tex]\(b\)[/tex] is a constant and [tex]\(x\)[/tex] is the variable of integration.

2. Apply the power rule for integration:
The power rule for integration states that [tex]\(\int x^n \, dx = \frac{x^{n+1}}{n+1} + C\)[/tex], where [tex]\(C\)[/tex] is the constant of integration, and [tex]\(n \neq -1\)[/tex].

3. Factor out the constant [tex]\(b\)[/tex]:
Since [tex]\(b\)[/tex] is a constant, we can factor it out of the integral:
[tex]\[ \int 2bx^3 \, dx = 2b \int x^3 \, dx \][/tex]

4. Integrate the remaining function [tex]\(x^3\)[/tex]:
Using the power rule for integration:
[tex]\[ \int x^3 \, dx = \frac{x^{3+1}}{3+1} = \frac{x^4}{4} \][/tex]

5. Multiply by the constant [tex]\(2b\)[/tex]:
Now we multiply the result by [tex]\(2b\)[/tex]:
[tex]\[ 2b \cdot \frac{x^4}{4} = \frac{2b x^4}{4} = \frac{b x^4}{2} \][/tex]

6. Include the constant of integration [tex]\(C\)[/tex]:
The final antiderivative includes an arbitrary constant [tex]\(C\)[/tex]:
[tex]\[ \int 2bx^3 \, dx = \frac{b x^4}{2} + C \][/tex]

So, the result of the integral [tex]\(\int 2bx^3 \, dx\)[/tex] is:
[tex]\[ \frac{b x^4}{2} + C \][/tex]
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