Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Connect with professionals on our platform to receive accurate answers to your questions quickly and efficiently. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
Of course! Let's solve this problem step-by-step based on the information provided about the arithmetic progression (A.P.).
### Given:
1. The 11th term [tex]\(a_{11}\)[/tex] is -31.
2. The 21st term [tex]\(a_{21}\)[/tex] is -71.
We will determine:
a) The first term ([tex]\(a\)[/tex]),
b) The common difference ([tex]\(d\)[/tex]),
c) The 15th term ([tex]\(a_{15}\)[/tex]).
### Step-by-Step Solution
An arithmetic progression (A.P.) is characterized by the formula for the [tex]\(n\)[/tex]-th term:
[tex]\[ a_n = a + (n-1)d \][/tex]
where:
- [tex]\(a_n\)[/tex] is the [tex]\(n\)[/tex]-th term,
- [tex]\(a\)[/tex] is the first term,
- [tex]\(d\)[/tex] is the common difference,
- [tex]\(n\)[/tex] is the position of the term.
#### Step 1: Setting up the equations
Using the given terms:
1. For the 11th term:
[tex]\[ a_{11} = a + 10d = -31 \][/tex]
2. For the 21st term:
[tex]\[ a_{21} = a + 20d = -71 \][/tex]
#### Step 2: Solve for the common difference ([tex]\(d\)[/tex])
We have two equations:
[tex]\[ 1) \quad a + 10d = -31 \][/tex]
[tex]\[ 2) \quad a + 20d = -71 \][/tex]
Subtracting equation (1) from equation (2) to eliminate [tex]\(a\)[/tex]:
[tex]\[ (a + 20d) - (a + 10d) = -71 - (-31) \][/tex]
[tex]\[ 20d - 10d = -71 + 31 \][/tex]
[tex]\[ 10d = -40 \][/tex]
Solving for [tex]\(d\)[/tex]:
[tex]\[ d = \frac{-40}{10} \][/tex]
[tex]\[ d = -4.0 \][/tex]
So, the common difference [tex]\(d\)[/tex] is [tex]\(-4.0\)[/tex].
#### Step 3: Solve for the first term ([tex]\(a\)[/tex])
Substitute the value of [tex]\(d\)[/tex] back into equation (1):
[tex]\[ a + 10(-4.0) = -31 \][/tex]
[tex]\[ a - 40 = -31 \][/tex]
Solving for [tex]\(a\)[/tex]:
[tex]\[ a = -31 + 40 \][/tex]
[tex]\[ a = 9 \][/tex]
So, the first term [tex]\(a\)[/tex] is [tex]\(9\)[/tex].
#### Step 4: Find the 15th term ([tex]\(a_{15}\)[/tex])
Using the formula for the [tex]\(n\)[/tex]-th term:
[tex]\[ a_{15} = a + (15-1)d \][/tex]
[tex]\[ a_{15} = 9 + 14(-4.0) \][/tex]
[tex]\[ a_{15} = 9 - 56 \][/tex]
[tex]\[ a_{15} = -47.0 \][/tex]
So, the 15th term [tex]\(a_{15}\)[/tex] is [tex]\(-47.0\)[/tex].
### Summary of Results
a) The first term [tex]\(a\)[/tex] is [tex]\(9\)[/tex].
b) The common difference [tex]\(d\)[/tex] is [tex]\(-4.0\)[/tex].
c) The 15th term [tex]\(a_{15}\)[/tex] is [tex]\(-47.0\)[/tex].
### Given:
1. The 11th term [tex]\(a_{11}\)[/tex] is -31.
2. The 21st term [tex]\(a_{21}\)[/tex] is -71.
We will determine:
a) The first term ([tex]\(a\)[/tex]),
b) The common difference ([tex]\(d\)[/tex]),
c) The 15th term ([tex]\(a_{15}\)[/tex]).
### Step-by-Step Solution
An arithmetic progression (A.P.) is characterized by the formula for the [tex]\(n\)[/tex]-th term:
[tex]\[ a_n = a + (n-1)d \][/tex]
where:
- [tex]\(a_n\)[/tex] is the [tex]\(n\)[/tex]-th term,
- [tex]\(a\)[/tex] is the first term,
- [tex]\(d\)[/tex] is the common difference,
- [tex]\(n\)[/tex] is the position of the term.
#### Step 1: Setting up the equations
Using the given terms:
1. For the 11th term:
[tex]\[ a_{11} = a + 10d = -31 \][/tex]
2. For the 21st term:
[tex]\[ a_{21} = a + 20d = -71 \][/tex]
#### Step 2: Solve for the common difference ([tex]\(d\)[/tex])
We have two equations:
[tex]\[ 1) \quad a + 10d = -31 \][/tex]
[tex]\[ 2) \quad a + 20d = -71 \][/tex]
Subtracting equation (1) from equation (2) to eliminate [tex]\(a\)[/tex]:
[tex]\[ (a + 20d) - (a + 10d) = -71 - (-31) \][/tex]
[tex]\[ 20d - 10d = -71 + 31 \][/tex]
[tex]\[ 10d = -40 \][/tex]
Solving for [tex]\(d\)[/tex]:
[tex]\[ d = \frac{-40}{10} \][/tex]
[tex]\[ d = -4.0 \][/tex]
So, the common difference [tex]\(d\)[/tex] is [tex]\(-4.0\)[/tex].
#### Step 3: Solve for the first term ([tex]\(a\)[/tex])
Substitute the value of [tex]\(d\)[/tex] back into equation (1):
[tex]\[ a + 10(-4.0) = -31 \][/tex]
[tex]\[ a - 40 = -31 \][/tex]
Solving for [tex]\(a\)[/tex]:
[tex]\[ a = -31 + 40 \][/tex]
[tex]\[ a = 9 \][/tex]
So, the first term [tex]\(a\)[/tex] is [tex]\(9\)[/tex].
#### Step 4: Find the 15th term ([tex]\(a_{15}\)[/tex])
Using the formula for the [tex]\(n\)[/tex]-th term:
[tex]\[ a_{15} = a + (15-1)d \][/tex]
[tex]\[ a_{15} = 9 + 14(-4.0) \][/tex]
[tex]\[ a_{15} = 9 - 56 \][/tex]
[tex]\[ a_{15} = -47.0 \][/tex]
So, the 15th term [tex]\(a_{15}\)[/tex] is [tex]\(-47.0\)[/tex].
### Summary of Results
a) The first term [tex]\(a\)[/tex] is [tex]\(9\)[/tex].
b) The common difference [tex]\(d\)[/tex] is [tex]\(-4.0\)[/tex].
c) The 15th term [tex]\(a_{15}\)[/tex] is [tex]\(-47.0\)[/tex].
We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.