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Sagot :
Let's solve the problem step-by-step.
We know that 25 grams of salt are dissolved in 150 milliliters (mL) of solution. Our task is to find how much solution can be made with 40 grams of salt, keeping the solution's concentration the same.
1. Determine the concentration of the initial solution:
- We start with 25 grams of salt making up 150 milliliters of solution.
- Therefore, the concentration of the solution is:
[tex]\[ \text{Concentration} = \frac{\text{Volume of Solution}}{\text{Amount of Salt}} \][/tex]
Plugging in the given values:
[tex]\[ \text{Concentration} = \frac{150 \, \text{mL}}{25 \, \text{g}} = 6 \, \text{mL/g} \][/tex]
- This means that for every gram of salt, we can make 6 milliliters of solution.
2. Calculate the volume of solution for 40 grams of salt:
- From the concentration we calculated, we know that each gram of salt makes 6 milliliters of solution.
- To find the volume of solution for 40 grams of salt:
[tex]\[ \text{Volume of New Solution} = 40 \, \text{g} \times 6 \, \text{mL/g} = 240 \, \text{mL} \][/tex]
- Therefore, using 40 grams of salt, we can make 240 milliliters of solution.
Final Answer:
Blank 1: 240
Blank 2: mL
We know that 25 grams of salt are dissolved in 150 milliliters (mL) of solution. Our task is to find how much solution can be made with 40 grams of salt, keeping the solution's concentration the same.
1. Determine the concentration of the initial solution:
- We start with 25 grams of salt making up 150 milliliters of solution.
- Therefore, the concentration of the solution is:
[tex]\[ \text{Concentration} = \frac{\text{Volume of Solution}}{\text{Amount of Salt}} \][/tex]
Plugging in the given values:
[tex]\[ \text{Concentration} = \frac{150 \, \text{mL}}{25 \, \text{g}} = 6 \, \text{mL/g} \][/tex]
- This means that for every gram of salt, we can make 6 milliliters of solution.
2. Calculate the volume of solution for 40 grams of salt:
- From the concentration we calculated, we know that each gram of salt makes 6 milliliters of solution.
- To find the volume of solution for 40 grams of salt:
[tex]\[ \text{Volume of New Solution} = 40 \, \text{g} \times 6 \, \text{mL/g} = 240 \, \text{mL} \][/tex]
- Therefore, using 40 grams of salt, we can make 240 milliliters of solution.
Final Answer:
Blank 1: 240
Blank 2: mL
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