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The upward component of the velocity of a projectile fired from a canon is 98.0 m/s, while the horizontal component is 400 m/s. What is the total initial velocity of the projectile?

Sagot :

MathPhys

Answer:

412 m/s

Explanation:

The horizontal component and vertical component are perpendicular to each other. Using Pythagorean theorem for right triangles, we can solve for the hypotenuse or total velocity vector.

Starting with Pythagorean theorem:

c² = a² + b²

Plugging in values:

c² = (98.0 m/s)² + (400 m/s)²

c² = 169,604 m²/s²

c ≈ 412 m/s

Rounded to three significant figures, the total velocity is 412 m/s.

View image MathPhys
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