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Use the conversion formulas for Celsius and Fahrenheit to find the missing values in the table.

[tex]\[
\begin{tabular}{|c|c|}
\hline \multicolumn{2}{|c|}{Temperature} \\
\hline Degrees Celsius & Degrees Fahrenheit \\
\hline 10 & $\square$ \\
\hline $\square$ & 87 \\
\hline -5 & $\square$ \\
\hline $\square$ & 10 \\
\hline
\end{tabular}
\][/tex]

Conversion formulas:
- [tex]\(F = \frac{9}{5}C + 32\)[/tex]
- [tex]\(C = \frac{5}{9}(F - 32)\)[/tex]

Sagot :

GinnyAnswer
Sure! Let's fill in the missing values in the table using the conversion formulas for Celsius and Fahrenheit.

1. Convert 10°C to °F:
- We use the formula [tex]\( F = (C \times \frac{9}{5}) + 32 \)[/tex].
- Substituting [tex]\( C = 10 \)[/tex], we get [tex]\( F = (10 \times \frac{9}{5}) + 32 \)[/tex].
- This simplifies to [tex]\( F = 50.0 \)[/tex].

So, 10°C is 50.0°F.

2. Convert 87°F to °C:
- We use the formula [tex]\( C = (F - 32) \times \frac{5}{9} \)[/tex].
- Substituting [tex]\( F = 87 \)[/tex], we get [tex]\( C = (87 - 32) \times \frac{5}{9} \)[/tex].
- This simplifies to [tex]\( C = 30.6 \)[/tex].

So, 87°F is 30.6°C.

3. Convert -5°C to °F:
- Using the formula [tex]\( F = (C \times \frac{9}{5}) + 32 \)[/tex].
- Substituting [tex]\( C = -5 \)[/tex], we get [tex]\( F = (-5 \times \frac{9}{5}) + 32 \)[/tex].
- This simplifies to [tex]\( F = 23.0 \)[/tex].

So, -5°C is 23.0°F.

4. Convert 10°F to °C:
- Using the formula [tex]\( C = (F - 32) \times \frac{5}{9} \)[/tex].
- Substituting [tex]\( F = 10 \)[/tex], we get [tex]\( C = (10 - 32) \times \frac{5}{9} \)[/tex].
- This simplifies to [tex]\( C = -12.2 \)[/tex].

So, 10°F is -12.2°C.

Now we can fill in the table:

\begin{tabular}{|c|c|}
\hline \multicolumn{2}{|c|}{ Temperature } \\
\hline Degrees Celsius & Degrees Fahrenheit \\
\hline 10 & 50.0 \\
\hline 30.6 & 87 \\
\hline -5 & 23.0 \\
\hline -12.2 & 10 \\
\hline
\end{tabular}
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