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Let [tex]f(x)=\frac{1}{x-5}[/tex] and [tex]g(x)=3x+12[/tex].

Then, [tex](f \circ g)(2)=\frac{1}{13}[/tex].

Find [tex](f \circ g)(x)[/tex].

Sagot :

Given the functions [tex]\( f(x) = \frac{1}{x - 5} \)[/tex] and [tex]\( g(x) = 3x + 12 \)[/tex], we want to find the composition [tex]\( (f \circ g)(x) \)[/tex].

The composition [tex]\( (f \circ g)(x) \)[/tex] means we first apply the function [tex]\( g(x) \)[/tex] and then apply the function [tex]\( f \)[/tex] to the result of [tex]\( g(x) \)[/tex].

1. Find [tex]\( g(x) \)[/tex]:
[tex]\[ g(x) = 3x + 12 \][/tex]

2. Substitute [tex]\( g(x) \)[/tex] into [tex]\( f \)[/tex]:
[tex]\[ f(g(x)) = f(3x + 12) \][/tex]

3. Apply [tex]\( f \)[/tex] to [tex]\( g(x) \)[/tex]:
[tex]\[ f(3x + 12) = \frac{1}{(3x + 12) - 5} \][/tex]

4. Simplify the denominator:
[tex]\[ (3x + 12) - 5 = 3x + 7 \][/tex]

5. Write the composed function:
[tex]\[ (f \circ g)(x) = \frac{1}{3x + 7} \][/tex]

So, the composition [tex]\( (f \circ g)(x) \)[/tex] is:

[tex]\[ (f \circ g)(x) = \frac{1}{3x + 7} \][/tex]

This could be confirmed by plugging the given answer for a specific value of [tex]\( x = 2 \)[/tex], but we already completed the steps to determine the final expression.
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