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Sagot :
To determine the molar mass of potassium permanganate ([tex]\( KMnO_4 \)[/tex]), we need to calculate the sum of the atomic masses of all the atoms present in one molecule of [tex]\( KMnO_4 \)[/tex].
Potassium permanganate is made up of one potassium atom (K), one manganese atom (Mn), and four oxygen atoms (O). The atomic masses of these elements are as follows:
- Potassium (K): 39.10 g/mol
- Manganese (Mn): 54.94 g/mol
- Oxygen (O): 16.00 g/mol
Now, let's sum the masses:
1. The mass contribution from one potassium atom (K) is 39.10 g/mol.
2. The mass contribution from one manganese atom (Mn) is 54.94 g/mol.
3. The mass contribution from four oxygen atoms (O) is [tex]\( 4 \times 16.00 \)[/tex] g/mol = 64.00 g/mol.
Adding these masses together gives the total molar mass of [tex]\( KMnO_4 \)[/tex]:
[tex]\[ 39.10 + 54.94 + 64.00 = 158.04 \][/tex]
Therefore, the molar mass of potassium permanganate ([tex]\( KMnO_4 \)[/tex]) is approximately 158 g/mol.
Hence, the correct answer is [tex]\( \boxed{158 \, g/mol} \)[/tex].
Potassium permanganate is made up of one potassium atom (K), one manganese atom (Mn), and four oxygen atoms (O). The atomic masses of these elements are as follows:
- Potassium (K): 39.10 g/mol
- Manganese (Mn): 54.94 g/mol
- Oxygen (O): 16.00 g/mol
Now, let's sum the masses:
1. The mass contribution from one potassium atom (K) is 39.10 g/mol.
2. The mass contribution from one manganese atom (Mn) is 54.94 g/mol.
3. The mass contribution from four oxygen atoms (O) is [tex]\( 4 \times 16.00 \)[/tex] g/mol = 64.00 g/mol.
Adding these masses together gives the total molar mass of [tex]\( KMnO_4 \)[/tex]:
[tex]\[ 39.10 + 54.94 + 64.00 = 158.04 \][/tex]
Therefore, the molar mass of potassium permanganate ([tex]\( KMnO_4 \)[/tex]) is approximately 158 g/mol.
Hence, the correct answer is [tex]\( \boxed{158 \, g/mol} \)[/tex].
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