Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Discover in-depth answers to your questions from a wide network of experts on our user-friendly Q&A platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
To find the measure of [tex]\(\angle Q\)[/tex], the smallest angle in a triangle with side lengths [tex]\(a = 4\)[/tex], [tex]\(b = 5\)[/tex], and [tex]\(c = 6\)[/tex], we can use the Law of Cosines. The Law of Cosines relates one angle of a triangle to the lengths of its sides and can be written as:
[tex]\[ a^2 = b^2 + c^2 - 2bc \cos(A) \][/tex]
We can rearrange this formula to solve for [tex]\(\cos(A)\)[/tex]:
[tex]\[ \cos(A) = \frac{b^2 + c^2 - a^2}{2bc} \][/tex]
We will also use the same formula to find the cosine of the other two angles. Given the side lengths, let's compute each angle step by step.
1. Finding [tex]\(\angle A\)[/tex] where [tex]\(a = 4\)[/tex], [tex]\(b = 5\)[/tex], and [tex]\(c = 6\)[/tex]:
[tex]\[ \cos(A) = \frac{5^2 + 6^2 - 4^2}{2 \cdot 5 \cdot 6} = \frac{25 + 36 - 16}{60} = \frac{45}{60} = 0.75 \][/tex]
[tex]\[ \angle A = \arccos(0.75) \][/tex]
Using a calculator, we find:
[tex]\[ \angle A \approx 41.41^{\circ} \][/tex]
2. Finding [tex]\(\angle B\)[/tex] where [tex]\(a = 4\)[/tex], [tex]\(b = 5\)[/tex], and [tex]\(c = 6\)[/tex]:
[tex]\[ \cos(B) = \frac{4^2 + 6^2 - 5^2}{2 \cdot 4 \cdot 6} = \frac{16 + 36 - 25}{48} = \frac{27}{48} = 0.5625 \][/tex]
[tex]\[ \angle B = \arccos(0.5625) \][/tex]
Using a calculator, we find:
[tex]\[ \angle B \approx 55.77^{\circ} \][/tex]
3. Finding [tex]\(\angle C\)[/tex] where [tex]\(a = 4\)[/tex], [tex]\(b = 5\)[/tex], and [tex]\(c = 6\)[/tex]:
[tex]\[ \cos(C) = \frac{4^2 + 5^2 - 6^2}{2 \cdot 4 \cdot 5} = \frac{16 + 25 - 36}{40} = \frac{5}{40} = 0.125 \][/tex]
[tex]\[ \angle C = \arccos(0.125) \][/tex]
Using a calculator, we find:
[tex]\[ \angle C \approx 82.82^{\circ} \][/tex]
We now have the measures of the three angles:
[tex]\[ \angle A \approx 41.41^{\circ}, \quad \angle B \approx 55.77^{\circ}, \quad \angle C \approx 82.82^{\circ} \][/tex]
The smallest angle is [tex]\(\angle A \approx 41.41^{\circ}\)[/tex], which, when rounded to the nearest whole number, is [tex]\(41^{\circ}\)[/tex].
Therefore, the measure of [tex]\(\angle Q\)[/tex], the smallest angle, is:
[tex]\[ \boxed{41^{\circ}} \][/tex]
[tex]\[ a^2 = b^2 + c^2 - 2bc \cos(A) \][/tex]
We can rearrange this formula to solve for [tex]\(\cos(A)\)[/tex]:
[tex]\[ \cos(A) = \frac{b^2 + c^2 - a^2}{2bc} \][/tex]
We will also use the same formula to find the cosine of the other two angles. Given the side lengths, let's compute each angle step by step.
1. Finding [tex]\(\angle A\)[/tex] where [tex]\(a = 4\)[/tex], [tex]\(b = 5\)[/tex], and [tex]\(c = 6\)[/tex]:
[tex]\[ \cos(A) = \frac{5^2 + 6^2 - 4^2}{2 \cdot 5 \cdot 6} = \frac{25 + 36 - 16}{60} = \frac{45}{60} = 0.75 \][/tex]
[tex]\[ \angle A = \arccos(0.75) \][/tex]
Using a calculator, we find:
[tex]\[ \angle A \approx 41.41^{\circ} \][/tex]
2. Finding [tex]\(\angle B\)[/tex] where [tex]\(a = 4\)[/tex], [tex]\(b = 5\)[/tex], and [tex]\(c = 6\)[/tex]:
[tex]\[ \cos(B) = \frac{4^2 + 6^2 - 5^2}{2 \cdot 4 \cdot 6} = \frac{16 + 36 - 25}{48} = \frac{27}{48} = 0.5625 \][/tex]
[tex]\[ \angle B = \arccos(0.5625) \][/tex]
Using a calculator, we find:
[tex]\[ \angle B \approx 55.77^{\circ} \][/tex]
3. Finding [tex]\(\angle C\)[/tex] where [tex]\(a = 4\)[/tex], [tex]\(b = 5\)[/tex], and [tex]\(c = 6\)[/tex]:
[tex]\[ \cos(C) = \frac{4^2 + 5^2 - 6^2}{2 \cdot 4 \cdot 5} = \frac{16 + 25 - 36}{40} = \frac{5}{40} = 0.125 \][/tex]
[tex]\[ \angle C = \arccos(0.125) \][/tex]
Using a calculator, we find:
[tex]\[ \angle C \approx 82.82^{\circ} \][/tex]
We now have the measures of the three angles:
[tex]\[ \angle A \approx 41.41^{\circ}, \quad \angle B \approx 55.77^{\circ}, \quad \angle C \approx 82.82^{\circ} \][/tex]
The smallest angle is [tex]\(\angle A \approx 41.41^{\circ}\)[/tex], which, when rounded to the nearest whole number, is [tex]\(41^{\circ}\)[/tex].
Therefore, the measure of [tex]\(\angle Q\)[/tex], the smallest angle, is:
[tex]\[ \boxed{41^{\circ}} \][/tex]
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.