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Use the equation to construct a table.

[tex]\[ y = \frac{1}{4} x + 2 \][/tex]

[tex]\[
\begin{tabular}{|c|c|}
\hline
$x$ & $y$ \\
\hline
-4 & \\
\hline
0 & \\
\hline
4 & \\
\hline
\end{tabular}
\][/tex]

Sagot :

GinnyAnswer
Let's construct the table for the given equation [tex]\( y = \frac{1}{4}x + 2 \)[/tex].

We'll calculate the value of [tex]\( y \)[/tex] for each given [tex]\( x \)[/tex] value: -4, 0, and 4.

1. For [tex]\( x = -4 \)[/tex]:
[tex]\[ y = \frac{1}{4}(-4) + 2 \][/tex]
[tex]\[ y = -1 + 2 \][/tex]
[tex]\[ y = 1 \][/tex]

2. For [tex]\( x = 0 \)[/tex]:
[tex]\[ y = \frac{1}{4}(0) + 2 \][/tex]
[tex]\[ y = 0 + 2 \][/tex]
[tex]\[ y = 2 \][/tex]

3. For [tex]\( x = 4 \)[/tex]:
[tex]\[ y = \frac{1}{4}(4) + 2 \][/tex]
[tex]\[ y = 1 + 2 \][/tex]
[tex]\[ y = 3 \][/tex]

Now we can fill in the table with the calculated values:

[tex]\[ \begin{tabular}{|c|c|} \hline $x$ & $y$ \\ \hline -4 & 1.0 \\ \hline 0 & 2.0 \\ \hline 4 & 3.0 \\ \hline \end{tabular} \][/tex]
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