Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Ask your questions and receive accurate answers from professionals with extensive experience in various fields on our platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
To calculate the arithmetic mean of the given distribution, we'll follow these steps:
1. Find the midpoints of each profit interval: The midpoint of an interval is the average of its lower and upper bounds. For each interval, we calculate:
- [tex]\(0-10\)[/tex]: Midpoint [tex]\((0 + 10) / 2 = 5\)[/tex]
- [tex]\(10-20\)[/tex]: Midpoint [tex]\((10 + 20) / 2 = 15\)[/tex]
- [tex]\(20-30\)[/tex]: Midpoint [tex]\((20 + 30) / 2 = 25\)[/tex]
- [tex]\(30-40\)[/tex]: Midpoint [tex]\((30 + 40) / 2 = 35\)[/tex]
- [tex]\(40-50\)[/tex]: Midpoint [tex]\((40 + 50) / 2 = 45\)[/tex]
- [tex]\(50-60\)[/tex]: Midpoint [tex]\((50 + 60) / 2 = 55\)[/tex]
So, the midpoints are [tex]\([5, 15, 25, 35, 45, 55]\)[/tex].
2. Determine the total number of stalls: Add the number of stalls in each profit interval:
[tex]\[ \text{Total number of stalls} = 126 + 18 + 27 + 20 + 17 + 6 = 214 \][/tex]
3. Calculate the weighted sum of the midpoints: Multiply each midpoint by the corresponding number of stalls, then sum these products:
[tex]\[ \begin{align*} \text{Weighted sum} &= (5 \times 126) + (15 \times 18) + (25 \times 27) + (35 \times 20) + (45 \times 17) + (55 \times 6) \\ &= 630 + 270 + 675 + 700 + 765 + 330 \\ &= 3370 \end{align*} \][/tex]
4. Calculate the arithmetic mean: The arithmetic mean is the weighted sum of the midpoints divided by the total number of stalls:
[tex]\[ \text{Arithmetic mean} = \frac{\text{Weighted sum}}{\text{Total number of stalls}} = \frac{3370}{214} \approx 15.748 \][/tex]
Hence, the arithmetic mean of the distribution is approximately [tex]\(15.748\)[/tex].
1. Find the midpoints of each profit interval: The midpoint of an interval is the average of its lower and upper bounds. For each interval, we calculate:
- [tex]\(0-10\)[/tex]: Midpoint [tex]\((0 + 10) / 2 = 5\)[/tex]
- [tex]\(10-20\)[/tex]: Midpoint [tex]\((10 + 20) / 2 = 15\)[/tex]
- [tex]\(20-30\)[/tex]: Midpoint [tex]\((20 + 30) / 2 = 25\)[/tex]
- [tex]\(30-40\)[/tex]: Midpoint [tex]\((30 + 40) / 2 = 35\)[/tex]
- [tex]\(40-50\)[/tex]: Midpoint [tex]\((40 + 50) / 2 = 45\)[/tex]
- [tex]\(50-60\)[/tex]: Midpoint [tex]\((50 + 60) / 2 = 55\)[/tex]
So, the midpoints are [tex]\([5, 15, 25, 35, 45, 55]\)[/tex].
2. Determine the total number of stalls: Add the number of stalls in each profit interval:
[tex]\[ \text{Total number of stalls} = 126 + 18 + 27 + 20 + 17 + 6 = 214 \][/tex]
3. Calculate the weighted sum of the midpoints: Multiply each midpoint by the corresponding number of stalls, then sum these products:
[tex]\[ \begin{align*} \text{Weighted sum} &= (5 \times 126) + (15 \times 18) + (25 \times 27) + (35 \times 20) + (45 \times 17) + (55 \times 6) \\ &= 630 + 270 + 675 + 700 + 765 + 330 \\ &= 3370 \end{align*} \][/tex]
4. Calculate the arithmetic mean: The arithmetic mean is the weighted sum of the midpoints divided by the total number of stalls:
[tex]\[ \text{Arithmetic mean} = \frac{\text{Weighted sum}}{\text{Total number of stalls}} = \frac{3370}{214} \approx 15.748 \][/tex]
Hence, the arithmetic mean of the distribution is approximately [tex]\(15.748\)[/tex].
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.