Welcome to Westonci.ca, your one-stop destination for finding answers to all your questions. Join our expert community now! Explore thousands of questions and answers from knowledgeable experts in various fields on our Q&A platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
To calculate the arithmetic mean of the given distribution, we'll follow these steps:
1. Find the midpoints of each profit interval: The midpoint of an interval is the average of its lower and upper bounds. For each interval, we calculate:
- [tex]\(0-10\)[/tex]: Midpoint [tex]\((0 + 10) / 2 = 5\)[/tex]
- [tex]\(10-20\)[/tex]: Midpoint [tex]\((10 + 20) / 2 = 15\)[/tex]
- [tex]\(20-30\)[/tex]: Midpoint [tex]\((20 + 30) / 2 = 25\)[/tex]
- [tex]\(30-40\)[/tex]: Midpoint [tex]\((30 + 40) / 2 = 35\)[/tex]
- [tex]\(40-50\)[/tex]: Midpoint [tex]\((40 + 50) / 2 = 45\)[/tex]
- [tex]\(50-60\)[/tex]: Midpoint [tex]\((50 + 60) / 2 = 55\)[/tex]
So, the midpoints are [tex]\([5, 15, 25, 35, 45, 55]\)[/tex].
2. Determine the total number of stalls: Add the number of stalls in each profit interval:
[tex]\[ \text{Total number of stalls} = 126 + 18 + 27 + 20 + 17 + 6 = 214 \][/tex]
3. Calculate the weighted sum of the midpoints: Multiply each midpoint by the corresponding number of stalls, then sum these products:
[tex]\[ \begin{align*} \text{Weighted sum} &= (5 \times 126) + (15 \times 18) + (25 \times 27) + (35 \times 20) + (45 \times 17) + (55 \times 6) \\ &= 630 + 270 + 675 + 700 + 765 + 330 \\ &= 3370 \end{align*} \][/tex]
4. Calculate the arithmetic mean: The arithmetic mean is the weighted sum of the midpoints divided by the total number of stalls:
[tex]\[ \text{Arithmetic mean} = \frac{\text{Weighted sum}}{\text{Total number of stalls}} = \frac{3370}{214} \approx 15.748 \][/tex]
Hence, the arithmetic mean of the distribution is approximately [tex]\(15.748\)[/tex].
1. Find the midpoints of each profit interval: The midpoint of an interval is the average of its lower and upper bounds. For each interval, we calculate:
- [tex]\(0-10\)[/tex]: Midpoint [tex]\((0 + 10) / 2 = 5\)[/tex]
- [tex]\(10-20\)[/tex]: Midpoint [tex]\((10 + 20) / 2 = 15\)[/tex]
- [tex]\(20-30\)[/tex]: Midpoint [tex]\((20 + 30) / 2 = 25\)[/tex]
- [tex]\(30-40\)[/tex]: Midpoint [tex]\((30 + 40) / 2 = 35\)[/tex]
- [tex]\(40-50\)[/tex]: Midpoint [tex]\((40 + 50) / 2 = 45\)[/tex]
- [tex]\(50-60\)[/tex]: Midpoint [tex]\((50 + 60) / 2 = 55\)[/tex]
So, the midpoints are [tex]\([5, 15, 25, 35, 45, 55]\)[/tex].
2. Determine the total number of stalls: Add the number of stalls in each profit interval:
[tex]\[ \text{Total number of stalls} = 126 + 18 + 27 + 20 + 17 + 6 = 214 \][/tex]
3. Calculate the weighted sum of the midpoints: Multiply each midpoint by the corresponding number of stalls, then sum these products:
[tex]\[ \begin{align*} \text{Weighted sum} &= (5 \times 126) + (15 \times 18) + (25 \times 27) + (35 \times 20) + (45 \times 17) + (55 \times 6) \\ &= 630 + 270 + 675 + 700 + 765 + 330 \\ &= 3370 \end{align*} \][/tex]
4. Calculate the arithmetic mean: The arithmetic mean is the weighted sum of the midpoints divided by the total number of stalls:
[tex]\[ \text{Arithmetic mean} = \frac{\text{Weighted sum}}{\text{Total number of stalls}} = \frac{3370}{214} \approx 15.748 \][/tex]
Hence, the arithmetic mean of the distribution is approximately [tex]\(15.748\)[/tex].
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.