Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Get expert answers to your questions quickly and accurately from our dedicated community of professionals. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

A taxicab starts at [tex]\((1, -2)\)[/tex] on the grid. It goes 3 blocks east and 1 block south to pick up a passenger. Then it goes 6 blocks west and 5 blocks north and drops off the passenger.

What are the coordinates of the point where the passenger was dropped off?

Sagot :

To solve this problem, let's break it down into a step-by-step process, following the movements of the taxicab.

1. Starting position:
The taxicab begins at coordinates [tex]\((1, -2)\)[/tex].

2. Movement to pick up the passenger:
- The taxicab moves 3 blocks east. To move east, we add 3 to the x-coordinate.
[tex]\[ x_{\text{new}} = 1 + 3 = 4 \][/tex]
- The taxicab moves 1 block south. To move south, we subtract 1 from the y-coordinate.
[tex]\[ y_{\text{new}} = -2 - 1 = -3 \][/tex]
- So, the coordinates at the passenger pick up point are [tex]\((4, -3)\)[/tex].

3. Movement to drop off the passenger:
- The taxicab moves 6 blocks west. To move west, we subtract 6 from the x-coordinate.
[tex]\[ x_{\text{new}} = 4 - 6 = -2 \][/tex]
- The taxicab moves 5 blocks north. To move north, we add 5 to the y-coordinate.
[tex]\[ y_{\text{new}} = -3 + 5 = 2 \][/tex]
- So, the coordinates at the passenger drop off point are [tex]\((-2, 2)\)[/tex].

Thus, after following these movements, the coordinates of the point where the passenger was dropped off are [tex]\((-2, 2)\)[/tex].