Let's outline a detailed, step-by-step solution to transform and combine these intermediate chemical equations according to the given instructions:
1. Initial Equations:
- Equation 1: [tex]\( 2 H_2(g) + O_2(g) \rightarrow 2 H_2O(l) \)[/tex]
- Equation 2: [tex]\( H_2(g) + F_2(g) \rightarrow 2 HF(g) \)[/tex]
2. Alter Equation 2 by Multiplying It by 2:
- Original Equation 2: [tex]\( H_2(g) + F_2(g) \rightarrow 2 HF(g) \)[/tex]
- Multiply all coefficients by 2:
[tex]\[
2[H_2(g) + F_2(g)] \rightarrow 4 HF(g)
\][/tex]
- The simplified form is:
[tex]\[
2 H_2(g) + 2 F_2(g) \rightarrow 4 HF(g)
\][/tex]
3. Reverse Equation 1:
- Original Equation 1: [tex]\( 2 H_2(g) + O_2(g) \rightarrow 2 H_2O(l) \)[/tex]
- Reverse the equation:
[tex]\[
2 H_2O(l) \rightarrow 2 H_2(g) + O_2(g)
\][/tex]
4. Resulting Altered Equations:
- Altered Equation 1 (Reversed): [tex]\( 2 H_2O(l) \rightarrow 2 H_2(g) + O_2(g) \)[/tex]
- Altered Equation 2 (Multiplied by 2): [tex]\( 2 H_2(g) + 2 F_2(g) \rightarrow 4 HF(g) \)[/tex]
Therefore, based on the given instructions, we have:
[tex]\[
2 H_2O(l) \rightarrow 2 H_2(g) + O_2(g)
\][/tex]
[tex]\[
2 H_2(g) + 2 F_2(g) \rightarrow 4 HF(g)
\][/tex]
The final forms of the altered equations are:
- Equation 1: [tex]\( 2 H_2O(l) \rightarrow 2 H_2(g) + O_2(g) \)[/tex]
- Equation 2: [tex]\( 2 H_2(g) + 2 F_2(g) \rightarrow 4 HF(g) \)[/tex]
These are the intermediates needed to form the desired chemical reaction with [tex]\(HF\)[/tex] and [tex]\(O_2\)[/tex] as the products using [tex]\(H_2O\)[/tex] and [tex]\(F_2\)[/tex].
