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isolate c
a=b(1/c-1/d)


Sagot :

A= b(1/c - 1/d)
A/b = 1/c -1/d
A/b + 1/d = 1/c
(A/b + 1/d) 1 = c

Answer: c = b/(a + 1).

Step-by-step explanation:

a = b(1/c - 1/d)

Expand RHS by first finding LCM

a = b((d — c)/cd)

a = (bd — bc)/cd

Then cross multiply

acd = bd — cd

Collect the terms having c to the LHS

acd + cd = bd

Factorise cd out of LHS

( a+ 1)dc = bd

c = bd/(a + 1)d

c = b/(a + 1).