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The Watsons are saving up to go on a family vacation in 3 years. They Invest [tex][tex][tex][tex]$2700 into an account with an annual interest rate of 1.36% compounded daily.
Answer the questions below. Do not round any intermediate computations, and round your final answers to the nearest cent. If necessary, refer to the
list of financial formulas. Assume there are 365 days in each year.
(a) Assuming no withdrawals are made, how much money is in the Watsons'
account after 3 years?
(b) How much interest is earned on the Watsons' investment after 3 years?
$[/tex][/tex][/tex][/tex]


Sagot :

Answer: a) $2812.44; b) $112.44

Step-by-step explanation:

To solve this problem, we will use the compound interest formula. The formula for compound interest is given by:

[tex]A = P\left(1 + \frac{r}{n}\right)^{nt}[/tex]

Where:

[tex]A[/tex] is the amount of money accumulated after

[tex]n[/tex] years, including interest.

[tex]P[/tex] is the principal amount (the initial amount of money).

[tex]r[/tex] is the annual interest rate (decimal).

[tex]n[/tex] is the number of times that interest is compounded per year.

[tex]t[/tex] is the time the money is invested for in years.

Given:
P = 2700 dollars

r = 0.0136 (1.36% annual interest rate)

n = 365 (compounded daily)

t = 3 years

a) Substitute the given values into the compound interest formula:

[tex]A = 2700\left(1 + \frac{0.0136}{365}\right)^{365 \times 3}[/tex]

[tex]A = 2700 \times \left(1.00003726027397\right)^{1095}[/tex]

[tex]A = \$2812.44[/tex]

b) The interest earned is the total amount minus the principal:

[tex]$Interest = A - P[/tex]

[tex]\text{Interest} = \$2812.44 - \$2700[/tex]

[tex]$Interest = \$112.44[/tex]

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