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Sagot :
Certainly! Let's solve the equation step-by-step:
Given the equation:
[tex]\[ 7(x + 3) = 28 \][/tex]
1. Distribute the 7 on the left side of the equation:
[tex]\[ 7 \cdot x + 7 \cdot 3 = 28 \][/tex]
[tex]\[ 7x + 21 = 28 \][/tex]
2. Subtract 21 from both sides to isolate the term with [tex]\( x \)[/tex]:
[tex]\[ 7x + 21 - 21 = 28 - 21 \][/tex]
[tex]\[ 7x = 7 \][/tex]
3. Divide both sides by 7 to solve for [tex]\( x \)[/tex]:
[tex]\[ x = \frac{7}{7} \][/tex]
4. Simplify the fraction:
[tex]\[ x = 1 \][/tex]
So, the solution to the equation [tex]\( 7(x + 3) = 28 \)[/tex] is:
[tex]\[ x = 1 \][/tex]
Given the equation:
[tex]\[ 7(x + 3) = 28 \][/tex]
1. Distribute the 7 on the left side of the equation:
[tex]\[ 7 \cdot x + 7 \cdot 3 = 28 \][/tex]
[tex]\[ 7x + 21 = 28 \][/tex]
2. Subtract 21 from both sides to isolate the term with [tex]\( x \)[/tex]:
[tex]\[ 7x + 21 - 21 = 28 - 21 \][/tex]
[tex]\[ 7x = 7 \][/tex]
3. Divide both sides by 7 to solve for [tex]\( x \)[/tex]:
[tex]\[ x = \frac{7}{7} \][/tex]
4. Simplify the fraction:
[tex]\[ x = 1 \][/tex]
So, the solution to the equation [tex]\( 7(x + 3) = 28 \)[/tex] is:
[tex]\[ x = 1 \][/tex]
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