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If [tex][tex]$f(x)=\sqrt{x-3}$[/tex][/tex], which inequality can be used to find the domain of [tex][tex]$f(x)$[/tex][/tex]?

A. [tex]\sqrt{x-3} \geq 0[/tex]
B. [tex]x-3 \geq 0[/tex]
C. [tex]\sqrt{x-3} \leq 0[/tex]
D. [tex]x-3 \leq 0[/tex]


Sagot :

To determine the domain of the function [tex]\( f(x) = \sqrt{x - 3} \)[/tex], we need to ensure that the expression inside the square root is non-negative. This is because the square root function is only defined for non-negative values in the context of real numbers.

Here are the detailed steps to find the appropriate inequality:

1. Recognize that for [tex]\( f(x) \)[/tex] to be defined, the expression inside the square root, [tex]\( x - 3 \)[/tex], must be greater than or equal to zero. This ensures that we avoid taking the square root of a negative number, which is not defined in real numbers.

2. Set up the inequality:
[tex]\[ x - 3 \geq 0 \][/tex]

3. Solve the inequality for [tex]\( x \)[/tex]:
[tex]\[ x - 3 \geq 0 \implies x \geq 3 \][/tex]

Therefore, the inequality [tex]\( x - 3 \geq 0 \)[/tex] can be used to find the domain of [tex]\( f(x) = \sqrt{x-3} \)[/tex]. This ensures that [tex]\( f(x) \)[/tex] is defined for all [tex]\( x \)[/tex] values that are greater than or equal to 3.

Hence, the correct inequality is:
[tex]\[ x - 3 \geq 0 \][/tex]