Answered

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Given [tex]n(x) = \frac{x}{2} + 1[/tex], what is the value of [tex]n(-8)[/tex]?

A. [tex]-4[/tex]
B. [tex]-3[/tex]
C. [tex]12[/tex]
D. [tex]8[/tex]

Sagot :

GinnyAnswer
To determine the value of the function [tex]\( n(x) = \frac{x}{2} + 1 \)[/tex] when [tex]\( x = -8 \)[/tex]:

1. Start with the function definition:
[tex]\[ n(x) = \frac{x}{2} + 1 \][/tex]

2. Substitute [tex]\( x = -8 \)[/tex] into the function:
[tex]\[ n(-8) = \frac{-8}{2} + 1 \][/tex]

3. Perform the division inside the function:
[tex]\[ \frac{-8}{2} = -4 \][/tex]

4. Now add 1 to the result of the division:
[tex]\[ -4 + 1 = -3 \][/tex]

Therefore, the value of [tex]\( n(-8) \)[/tex] is [tex]\(-3\)[/tex].

The correct choice among the given options is [tex]\(-3\)[/tex].
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