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\begin{tabular}{|c|c|c|c|c|}
\cline{2-5}
& Compound & \begin{tabular}{c}
Mass Na \\
(grams)
\end{tabular} & \begin{tabular}{c}
Mass Z \\
(grams)
\end{tabular} & Formula \\
\cline{2-5}
Calculate the mass of element "Z" in & A & 12.00 & 2.44 & [tex]$Na_3Z$[/tex] \\
\hline
& B & 3.45 & 0.700 & ? \\
\hline
compound C. & C & 14.00 & ? & [tex]$Na_3Z$[/tex] \\
\hline
& D & 25.00 & 30.47 & ? \\
\hline
\end{tabular}

Possible masses of Z:
- 69.02 grams Z
- 2.84 grams Z
- 4.92 grams Z
- 0.352 grams Z

Sagot :

Sure, let's go through the solution step-by-step.

### Step 1: Analyze Compound A
We are given the mass of Sodium (Na) and element Z in compound A:
- Mass of Na (in A): [tex]\(12.00\)[/tex] grams
- Mass of Z (in A): [tex]\(2.44\)[/tex] grams

Since the formula for compound A is [tex]\( \text{Na}_3 \text{Z} \)[/tex], the molar ratio of Na to Z can be represented as the ratio of their masses:
[tex]\[ \text{Molar Mass Ratio of Na to Z in A} = \frac{\text{Mass of Na}}{\text{Mass of Z}} = \frac{12.00}{2.44} \][/tex]

### Step 2: Examine Compound B
We are given the mass of Sodium (Na) and element Z in Compound B:
- Mass of Na (in B): [tex]\(3.45\)[/tex] grams
- Mass of Z (in B): [tex]\(0.700\)[/tex] grams

Since we aim to use the same molar ratio for consistency, we can calculate the mass of Z in Compound B using the given intact values.

### Step 3: Determine Mass of Z in Compound C
For Compound C, we know:
- Mass of Na (in C): [tex]\(14.00\)[/tex] grams
- Formula: [tex]\( \text{Na}_3 \text{Z} \)[/tex]

Since the compound forms the same molar ratio as in Compound A, to find the mass of Z in Compound C, we use:

[tex]\[ \text{Mass of Z (in C)} = \frac{\text{Mass of Na (in C)}}{\text{Molar Mass Ratio of Na to Z in A}} \][/tex]

### Step 4: Given Data for Compound D
- Mass of Na (in D): [tex]\(25.00\)[/tex] grams
- Mass of Z (in D): [tex]\(30.47\)[/tex] grams

Since these values are provided, we don't need any further calculations for Compound D.

### Calculated Results
Summarizing the calculated masses of element Z:

1. Compound A:
[tex]\[ \text{Mass of Z} = 2.44 \, \text{grams} \][/tex]

2. Compound B:
[tex]\[ \text{Mass of Z} = 0.700 \, \text{grams} \][/tex]

3. Compound C:
[tex]\[ \text{Mass of Z} = 2.8466666666666667 \, \text{grams} \][/tex]

4. Compound D:
[tex]\[ \text{Mass of Z} = 30.47 \, \text{grams} \][/tex]

Thus, from the provided data and calculations:

- For Compound A, the mass of Z is [tex]\(2.44\)[/tex] grams.
- For Compound B, the mass of Z is [tex]\(0.700\)[/tex] grams.
- For Compound C, the calculated mass of Z is [tex]\(2.8466666666666667\)[/tex] grams.
- For Compound D, the mass of Z is [tex]\(30.47\)[/tex] grams.

Hence, the mass of element Z in each specified compound is correctly calculated in a consistent manner, preserving the ratio consistent with Compound A.