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Question 2 of 10

Here is a table of values for [tex]\( y = f(x) \)[/tex].

\begin{tabular}{|c|c|c|c|c|c|c|c|c|c|}
\hline
[tex]\( x \)[/tex] & -5 & -3 & 0 & 2 & 6 & 7 & 9 & 10 & 13 \\
\hline
[tex]\( f(x) \)[/tex] & 1 & 2 & 3 & 0 & 1 & 2 & 3 & 0 & 1 \\
\hline
\end{tabular}

Mark the statements that are true:

A. [tex]\( f(-3) = 2 \)[/tex]

B. The range for [tex]\( f(x) \)[/tex] is all real numbers.

C. [tex]\( f(0) = 10 \)[/tex]

D. The domain for [tex]\( f(x) \)[/tex] is the set [tex]\( \{-5, -3, 0, 2, 6, 7, 9, 10, 13\} \)[/tex].

Sagot :

Let's evaluate the given statements based on the table provided:

### Statement A: [tex]\( f(-3) = 2 \)[/tex]
Looking at the table, when [tex]\( x = -3 \)[/tex], the value of [tex]\( f(x) \)[/tex] is 2. Therefore, [tex]\( f(-3) = 2 \)[/tex] is a true statement.

### Statement B: The range for [tex]\( f(x) \)[/tex] is all real numbers
The range of a function is the set of all possible output values (y-values). From the table, the output values (y-values) are \{1, 2, 3, 0, 1, 2, 3, 0, 1\}. The unique values here are \{0, 1, 2, 3\}. Since the range only includes 0, 1, 2, and 3, it is not all real numbers. Hence, this statement is false.

### Statement C: [tex]\( f(0) = 10 \)[/tex]
Checking the table, when [tex]\( x = 0 \)[/tex], the value of [tex]\( f(x) \)[/tex] is 3, not 10. Therefore, [tex]\( f(0) = 10 \)[/tex] is a false statement.

### Statement D: The domain for [tex]\( f(x) \)[/tex] is the set [tex]\(\{-5, -3, 0, 2, 6, 7, 9, 10, 13\}\)[/tex]
The domain of a function is the set of all possible input values (x-values). From the table, the x-values are \{-5, -3, 0, 2, 6, 7, 9, 10, 13\}. This exactly matches the set given in the statement. Therefore, this statement is true.

### Conclusion
Based on the evaluation, the true statements are:
- A. [tex]\( f(-3) = 2 \)[/tex]
- D. The domain for [tex]\( f(x) \)[/tex] is the set [tex]\(\{-5, -3, 0, 2, 6, 7, 9, 10, 13\}\)[/tex]

Thus, the answers are:
- [tex]\( ( \text{True, False, False, True} ) \)[/tex]