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What are the roots of the equation [tex](x+7)^2=49[/tex]?

[tex]x = \{ \square , \square \}[/tex]


Sagot :

To find the roots of the equation [tex]\((x + 7)^2 = 49\)[/tex], we can follow these steps:

1. Start by recognizing that [tex]\((x + 7)^2 = 49\)[/tex] is a quadratic equation. To solve for [tex]\(x\)[/tex], we'll first need to take the square root on both sides of the equation.

2. Taking the square root of both sides, we get:
[tex]\[ x + 7 = \pm \sqrt{49} \][/tex]

3. The square root of 49 is 7. Therefore, we can rewrite the equation as:
[tex]\[ x + 7 = \pm 7 \][/tex]

4. This gives us two separate equations to solve for [tex]\(x\)[/tex]:
[tex]\[ x + 7 = 7 \quad \text{and} \quad x + 7 = -7 \][/tex]

5. Solving the first equation [tex]\(x + 7 = 7\)[/tex]:
[tex]\[ x + 7 = 7 \][/tex]
Subtract 7 from both sides:
[tex]\[ x = 0 \][/tex]

6. Solving the second equation [tex]\(x + 7 = -7\)[/tex]:
[tex]\[ x + 7 = -7 \][/tex]
Subtract 7 from both sides:
[tex]\[ x = -14 \][/tex]

7. Therefore, the roots of the equation [tex]\((x + 7)^2 = 49\)[/tex] are:
[tex]\[ x = \{0, -14\} \][/tex]

Hence, the roots of the equation [tex]\((x + 7)^2 = 49\)[/tex] are [tex]\(0.0\)[/tex] and [tex]\(-14.0\)[/tex].
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