Discover the best answers at Westonci.ca, where experts share their insights and knowledge with you. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
To find the coordinates of a point that is a given fraction of the way from one point to another, you can use the section formula for dividing a line in a given ratio. Here, we are asked for the coordinates of a point that is [tex]\(\frac{3}{8}\)[/tex] of the way from point [tex]\(A(-8, -9)\)[/tex] to point [tex]\(B(24, -1)\)[/tex].
Here's the step-by-step solution:
1. Identify the coordinates of the given points:
- Point [tex]\(A\)[/tex] has coordinates [tex]\((-8, -9)\)[/tex].
- Point [tex]\(B\)[/tex] has coordinates [tex]\((24, -1)\)[/tex].
2. Identify the fraction of the way from [tex]\(A\)[/tex] to [tex]\(B\)[/tex]:
- The fraction is [tex]\(\frac{3}{8}\)[/tex].
3. Determine the formula for the coordinates of the point [tex]\(P\)[/tex] that divides the line segment [tex]\(AB\)[/tex] in the ratio [tex]\(k:m\)[/tex]:
- If [tex]\(P\)[/tex] divides the line segment [tex]\(AB\)[/tex] in the ratio [tex]\(k:m\)[/tex], the coordinates of [tex]\(P(x, y)\)[/tex] are given by:
[tex]\[ P_x = \frac{m \cdot A_x + k \cdot B_x}{m + k} \][/tex]
[tex]\[ P_y = \frac{m \cdot A_y + k \cdot B_y}{m + k} \][/tex]
4. Apply the ratio for [tex]\(\frac{3}{8}\)[/tex]:
- Here, [tex]\(k = 3\)[/tex] and [tex]\(m = 8 - 3 = 5\)[/tex] (since [tex]\(\frac{3}{8}\)[/tex] of the way corresponds to a ratio of [tex]\(3\)[/tex] parts to [tex]\(5\)[/tex] parts).
5. Calculate the x-coordinate of the point:
[tex]\[ P_x = \frac{5 \cdot (-8) + 3 \cdot 24}{5 + 3} \][/tex]
[tex]\[ P_x = \frac{5 \cdot (-8) + 3 \cdot 24}{8} \][/tex]
[tex]\[ P_x = \frac{-40 + 72}{8} \][/tex]
[tex]\[ P_x = \frac{32}{8} \][/tex]
[tex]\[ P_x = 4 \][/tex]
6. Calculate the y-coordinate of the point:
[tex]\[ P_y = \frac{5 \cdot (-9) + 3 \cdot (-1)}{5 + 3} \][/tex]
[tex]\[ P_y = \frac{5 \cdot (-9) + 3 \cdot (-1)}{8} \][/tex]
[tex]\[ P_y = \frac{-45 + (-3)}{8} \][/tex]
[tex]\[ P_y = \frac{-48}{8} \][/tex]
[tex]\[ P_y = -6 \][/tex]
Therefore, the coordinates of the point that is [tex]\(\frac{3}{8}\)[/tex] of the way from [tex]\(A(-8, -9)\)[/tex] to [tex]\(B(24, -1)\)[/tex] are [tex]\((4, -6)\)[/tex].
So, the answer is [tex]\( \boxed{(4,-6)} \)[/tex].
Here's the step-by-step solution:
1. Identify the coordinates of the given points:
- Point [tex]\(A\)[/tex] has coordinates [tex]\((-8, -9)\)[/tex].
- Point [tex]\(B\)[/tex] has coordinates [tex]\((24, -1)\)[/tex].
2. Identify the fraction of the way from [tex]\(A\)[/tex] to [tex]\(B\)[/tex]:
- The fraction is [tex]\(\frac{3}{8}\)[/tex].
3. Determine the formula for the coordinates of the point [tex]\(P\)[/tex] that divides the line segment [tex]\(AB\)[/tex] in the ratio [tex]\(k:m\)[/tex]:
- If [tex]\(P\)[/tex] divides the line segment [tex]\(AB\)[/tex] in the ratio [tex]\(k:m\)[/tex], the coordinates of [tex]\(P(x, y)\)[/tex] are given by:
[tex]\[ P_x = \frac{m \cdot A_x + k \cdot B_x}{m + k} \][/tex]
[tex]\[ P_y = \frac{m \cdot A_y + k \cdot B_y}{m + k} \][/tex]
4. Apply the ratio for [tex]\(\frac{3}{8}\)[/tex]:
- Here, [tex]\(k = 3\)[/tex] and [tex]\(m = 8 - 3 = 5\)[/tex] (since [tex]\(\frac{3}{8}\)[/tex] of the way corresponds to a ratio of [tex]\(3\)[/tex] parts to [tex]\(5\)[/tex] parts).
5. Calculate the x-coordinate of the point:
[tex]\[ P_x = \frac{5 \cdot (-8) + 3 \cdot 24}{5 + 3} \][/tex]
[tex]\[ P_x = \frac{5 \cdot (-8) + 3 \cdot 24}{8} \][/tex]
[tex]\[ P_x = \frac{-40 + 72}{8} \][/tex]
[tex]\[ P_x = \frac{32}{8} \][/tex]
[tex]\[ P_x = 4 \][/tex]
6. Calculate the y-coordinate of the point:
[tex]\[ P_y = \frac{5 \cdot (-9) + 3 \cdot (-1)}{5 + 3} \][/tex]
[tex]\[ P_y = \frac{5 \cdot (-9) + 3 \cdot (-1)}{8} \][/tex]
[tex]\[ P_y = \frac{-45 + (-3)}{8} \][/tex]
[tex]\[ P_y = \frac{-48}{8} \][/tex]
[tex]\[ P_y = -6 \][/tex]
Therefore, the coordinates of the point that is [tex]\(\frac{3}{8}\)[/tex] of the way from [tex]\(A(-8, -9)\)[/tex] to [tex]\(B(24, -1)\)[/tex] are [tex]\((4, -6)\)[/tex].
So, the answer is [tex]\( \boxed{(4,-6)} \)[/tex].
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.