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Sagot :
To solve for [tex]\( k \)[/tex] in the equation [tex]\( 3x(x - 2k) = 3x^2 - 48x \)[/tex], follow these steps:
1. Expand the left-hand side:
[tex]\[ 3x(x - 2k) = 3x^2 - 6kx \][/tex]
2. Compare the expanded left-hand side to the right-hand side:
[tex]\[ 3x^2 - 6kx = 3x^2 - 48x \][/tex]
3. Since both expressions must be equal for all [tex]\( x \)[/tex], compare the coefficients of [tex]\( x \)[/tex] on both sides of the equation:
- Coefficient of [tex]\( x^2 \)[/tex]: [tex]\( 3 \)[/tex]
- Coefficient of [tex]\( x \)[/tex]: [tex]\( -6k \)[/tex]
Therefore, by comparing the coefficients of [tex]\( x \)[/tex]:
[tex]\[ -6k = -48 \][/tex]
4. Solve for [tex]\( k \)[/tex] by isolating [tex]\( k \)[/tex] on one side of the equation:
[tex]\[ -6k = -48 \][/tex]
[tex]\[ k = \frac{-48}{-6} \][/tex]
[tex]\[ k = 8 \][/tex]
Therefore, the value of [tex]\( k \)[/tex] is [tex]\( \boxed{8} \)[/tex].
1. Expand the left-hand side:
[tex]\[ 3x(x - 2k) = 3x^2 - 6kx \][/tex]
2. Compare the expanded left-hand side to the right-hand side:
[tex]\[ 3x^2 - 6kx = 3x^2 - 48x \][/tex]
3. Since both expressions must be equal for all [tex]\( x \)[/tex], compare the coefficients of [tex]\( x \)[/tex] on both sides of the equation:
- Coefficient of [tex]\( x^2 \)[/tex]: [tex]\( 3 \)[/tex]
- Coefficient of [tex]\( x \)[/tex]: [tex]\( -6k \)[/tex]
Therefore, by comparing the coefficients of [tex]\( x \)[/tex]:
[tex]\[ -6k = -48 \][/tex]
4. Solve for [tex]\( k \)[/tex] by isolating [tex]\( k \)[/tex] on one side of the equation:
[tex]\[ -6k = -48 \][/tex]
[tex]\[ k = \frac{-48}{-6} \][/tex]
[tex]\[ k = 8 \][/tex]
Therefore, the value of [tex]\( k \)[/tex] is [tex]\( \boxed{8} \)[/tex].
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