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6. Si: [tex]\frac{a}{b} = \frac{4}{5}[/tex] y [tex]4a - 3b = 7[/tex], halla [tex]a + b[/tex].

Sagot :

Para resolver el sistema de ecuaciones dado, seguimos estos pasos detallados:

1. Las ecuaciones proporcionadas son:
[tex]\[ \frac{a}{b} = \frac{4}{5} \][/tex]
y
[tex]\[ 4a - 3b = 7 \][/tex]

2. Primero, vamos a expresar [tex]\(a\)[/tex] en términos de [tex]\(b\)[/tex] usando la primera ecuación:
[tex]\[ \frac{a}{b} = \frac{4}{5} \][/tex]
Esto se puede reescribir como:
[tex]\[ a = \frac{4}{5} b \][/tex]

3. Ahora sustituimos esta expresión de [tex]\(a\)[/tex] en la segunda ecuación:
[tex]\[ 4 \left(\frac{4}{5} b\right) - 3b = 7 \][/tex]

4. Simplificamos la expresión:
[tex]\[ \frac{16}{5} b - 3b = 7 \][/tex]

5. Para combinar los términos similares, es útil tener un denominador común:
[tex]\[ \frac{16b - 15b}{5} = 7 \][/tex]

6. Simplificamos el numerador:
[tex]\[ \frac{b}{5} = 7 \][/tex]

7. Despejamos [tex]\(b\)[/tex]:
[tex]\[ b = 7 \cdot 5 \][/tex]
[tex]\[ b = 35 \][/tex]

8. Ahora que tenemos el valor de [tex]\(b\)[/tex], podemos encontrar [tex]\(a\)[/tex] usando la ecuación [tex]\(a = \frac{4}{5} b\)[/tex]:
[tex]\[ a = \frac{4}{5} \cdot 35 \][/tex]
[tex]\[ a = 28 \][/tex]

9. Finalmente, hallamos [tex]\(a + b\)[/tex]:
[tex]\[ a + b = 28 + 35 \][/tex]
[tex]\[ a + b = 63 \][/tex]

Por lo tanto, la suma [tex]\(a + b\)[/tex] es [tex]\(63\)[/tex].
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