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In a dihybrid cross for round and yellow seeds ([tex]RrYy \times RrYy[/tex]), what is the probability of having green and wrinkled seeds?

Key:
[tex]\[
\begin{aligned}
R &= \text{round} \\
r &= \text{wrinkled} \\
Y &= \text{yellow} \\
y &= \text{green}
\end{aligned}
\][/tex]

A. 1:16
B. 3:16
C. 8:16
D. 9:16

Sagot :

GinnyAnswer
To determine the probability of having green and wrinkled seeds from a dihybrid cross RrYy x RrYy, follow these steps:

1. Understand the phenotypes and genotypes:
- Round (R) and wrinkled (r) seeds represent one trait (shape).
- Yellow (Y) and green (y) seeds represent another trait (color).
- R and Y are dominant alleles, while r and y are recessive alleles.

2. Establish the parental genotypes:
- Both parents in the cross are RrYy.

3. Determine the possible gametes:
- Each parent can produce four types of gametes due to the assortment of the alleles: RY, Ry, rY, ry.

4. Create a Punnett Square:
- A 4x4 Punnett square helps to identify all potential combinations of these gametes (16 possible genotypes).

5. Analyze the offspring phenotypes:
- We are interested in the green and wrinkled seeds, which correspond to the genotype rryy.

6. Calculate the probability:
- Examine the Punnett square and count how many times the genotype rryy appears among the 16 possible genotypes.
- The result will show that rryy appears once.

Thus, the probability of having green and wrinkled seeds (rryy) is:
[tex]\[ \frac{1}{16} \][/tex]

Which can also be written as:

[tex]\[ 1:16 \][/tex]

Therefore, the correct answer is 1:16.
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