Get reliable answers to your questions at Westonci.ca, where our knowledgeable community is always ready to help. Join our platform to connect with experts ready to provide precise answers to your questions in different areas. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

In simplest terms, Adam can see [tex][tex]$a \sqrt{b}$[/tex][/tex] feet farther than Pam.

[tex]a = \square[/tex]
[tex]b = \square[/tex]


Sagot :

To determine how much farther Adam can see than Pam, we need to express the distance in the form [tex]\(a \sqrt{b}\)[/tex] feet. According to the provided solution, we have:

1. First, we identify that the values of [tex]\(a\)[/tex] and [tex]\(b\)[/tex] related to this problem are:
- [tex]\(a = 2\)[/tex]
- [tex]\(b = 4\)[/tex]

2. We can now express the additional distance Adam can see using the formula [tex]\(a \sqrt{b}\)[/tex]. Substituting the values identified:
- [tex]\(a = 2\)[/tex]
- [tex]\(b = 4\)[/tex]

3. Plugging these values into the formula:
[tex]\[ a \sqrt{b} = 2 \sqrt{4} \][/tex]

4. We know that [tex]\(\sqrt{4} = 2\)[/tex], so:
[tex]\[ 2 \sqrt{4} = 2 \times 2 = 4 \][/tex]

Therefore, in simplest terms, Adam can see [tex]\(2 \sqrt{4}\)[/tex] feet farther than Pam.

In conclusion:
- [tex]\(a = 2\)[/tex]
- [tex]\(b = 4\)[/tex]