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Which point lies on the line described by the equation below?

[tex]\[ y + 3 = 2(x - 1) \][/tex]

A. [tex]\((0,0)\)[/tex]

B. [tex]\((-1,-6)\)[/tex]

C. [tex]\((1,-3)\)[/tex]

D. [tex]\((2,9)\)[/tex]

E. [tex]\((2,1)\)[/tex]

F. [tex]\((1,-4)\)[/tex]

Sagot :

GinnyAnswer
To determine which point lies on the line described by the equation [tex]\( y + 3 = 2(x - 1) \)[/tex], let's first rewrite the equation in a more familiar form:
[tex]\[ y + 3 = 2(x - 1) \][/tex]

Step 1: Distribute the 2 on the right side:
[tex]\[ y + 3 = 2x - 2 \][/tex]

Step 2: Subtract 3 from both sides to solve for [tex]\( y \)[/tex]:
[tex]\[ y = 2x - 2 - 3 \][/tex]
[tex]\[ y = 2x - 5 \][/tex]

The equation in slope-intercept form is:
[tex]\[ y = 2x - 5 \][/tex]

Now, we'll test each point to see if it satisfies this equation.

Point A: [tex]\((0,0)\)[/tex]

Substitute [tex]\( x = 0 \)[/tex] and [tex]\( y = 0 \)[/tex] into the equation [tex]\( y = 2x - 5 \)[/tex]:
[tex]\[ 0 = 2(0) - 5 \][/tex]
[tex]\[ 0 = -5 \][/tex]
This is false. So, point [tex]\( (0, 0) \)[/tex] does not lie on the line.

Point B: [tex]\((-1,-6)\)[/tex]

Substitute [tex]\( x = -1 \)[/tex] and [tex]\( y = -6 \)[/tex] into the equation [tex]\( y = 2x - 5 \)[/tex]:
[tex]\[ -6 = 2(-1) - 5 \][/tex]
[tex]\[ -6 = -2 - 5 \][/tex]
[tex]\[ -6 = -7 \][/tex]
This is false. So, point [tex]\( (-1, -6) \)[/tex] does not lie on the line.

Point C: [tex]\((1,-3)\)[/tex]

Substitute [tex]\( x = 1 \)[/tex] and [tex]\( y = -3 \)[/tex] into the equation [tex]\( y = 2x - 5 \)[/tex]:
[tex]\[ -3 = 2(1) - 5 \][/tex]
[tex]\[ -3 = 2 - 5 \][/tex]
[tex]\[ -3 = -3 \][/tex]
This is true. So, point [tex]\( (1, -3) \)[/tex] does lie on the line.

Point D: [tex]\((2,9)\)[/tex]

Substitute [tex]\( x = 2 \)[/tex] and [tex]\( y = 9 \)[/tex] into the equation [tex]\( y = 2x - 5 \)[/tex]:
[tex]\[ 9 = 2(2) - 5 \][/tex]
[tex]\[ 9 = 4 - 5 \][/tex]
[tex]\[ 9 = -1 \][/tex]
This is false. So, point [tex]\( (2, 9) \)[/tex] does not lie on the line.

Point E: [tex]\((2,1)\)[/tex]

Substitute [tex]\( x = 2 \)[/tex] and [tex]\( y = 1 \)[/tex] into the equation [tex]\( y = 2x - 5 \)[/tex]:
[tex]\[ 1 = 2(2) - 5 \][/tex]
[tex]\[ 1 = 4 - 5 \][/tex]
[tex]\[ 1 = -1 \][/tex]
This is false. So, point [tex]\( (2, 1) \)[/tex] does not lie on the line.

Point F: [tex]\((1,-4)\)[/tex]

Substitute [tex]\( x = 1 \)[/tex] and [tex]\( y = -4 \)[/tex] into the equation [tex]\( y = 2x - 5 \)[/tex]:
[tex]\[ -4 = 2(1) - 5 \][/tex]
[tex]\[ -4 = 2 - 5 \][/tex]
[tex]\[ -4 = -3 \][/tex]
This is false. So, point [tex]\( (1, -4) \)[/tex] does not lie on the line.

Therefore, the point that lies on the line described by the equation [tex]\( y + 3 = 2(x - 1) \)[/tex] is:

[tex]\[ \boxed{(1, -3)} \][/tex]
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