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What is the perimeter of a polygon with vertices at [tex]$(-2, 1)$[/tex], [tex]$(-2, 7)$[/tex], [tex]$(1, 11)$[/tex], [tex]$(4, 7)$[/tex], and [tex]$(4, 1)$[/tex]?

Enter your answer in the box. Do not round any side lengths.


Sagot :

To find the perimeter of the given polygon with vertices at [tex]\((-2,1)\)[/tex], [tex]\((-2,7)\)[/tex], [tex]\((1,11)\)[/tex], [tex]\((4,7)\)[/tex], and [tex]\((4,1)\)[/tex], follow these steps to calculate the distance between each pair of consecutive vertices:

1. Calculate the distance between [tex]\((-2,1)\)[/tex] and [tex]\((-2,7)\)[/tex]:

[tex]\[ d_1 = \sqrt{( -2 - (-2) )^2 + ( 7 - 1 )^2} = \sqrt{0 + 6^2} = \sqrt{36} = 6 \][/tex]

2. Calculate the distance between [tex]\((-2,7)\)[/tex] and [tex]\((1,11)\)[/tex]:

[tex]\[ d_2 = \sqrt{( 1 - (-2) )^2 + ( 11 - 7 )^2} = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5 \][/tex]

3. Calculate the distance between [tex]\((1,11)\)[/tex] and [tex]\((4,7)\)[/tex]:

[tex]\[ d_3 = \sqrt{( 4 - 1 )^2 + ( 7 - 11 )^2} = \sqrt{3^2 + (-4)^2} = \sqrt{9 + 16} = \sqrt{25} = 5 \][/tex]

4. Calculate the distance between [tex]\((4,7)\)[/tex] and [tex]\((4,1)\)[/tex]:

[tex]\[ d_4 = \sqrt{( 4 - 4 )^2 + ( 1 - 7 )^2} = \sqrt{0 + (-6)^2} = \sqrt{36} = 6 \][/tex]

5. Calculate the distance between [tex]\((4,1)\)[/tex] and [tex]\((-2,1)\)[/tex]:

[tex]\[ d_5 = \sqrt{( -2 - 4 )^2 + ( 1 - 1 )^2} = \sqrt{(-6)^2 + 0} = \sqrt{36} = 6 \][/tex]

Now, sum the distances to find the perimeter of the polygon:

[tex]\[ \text{Perimeter} = d_1 + d_2 + d_3 + d_4 + d_5 = 6 + 5 + 5 + 6 + 6 = 28 \][/tex]

Thus, the perimeter of the polygon is:

[tex]\[ \boxed{28.0} \][/tex]