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To improve the formatting, correct any errors, and ensure the question makes sense, here is the revised version:

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Perform the division:

[tex]\[ 23 \div 449 \][/tex]
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Note: Since the original text seems to imply a division problem but is poorly formatted and nonsensical, I have corrected it to reflect a proper division operation.

Sagot :

Sure, let's solve the division problem step-by-step.

We need to divide 449 by 23.

1. Determine how many times 23 can go into the first part of 449.
- Look at the first two digits, 44.
- 23 goes into 44 one time because [tex]\(23 \times 1 = 23\)[/tex], which is less than 44.
- Write 1 above the 44.

2. Subtract 23 from 44.
- [tex]\(44 - 23 = 21\)[/tex].
- Write 21 below 44.

3. Bring down the next digit (which is 9) to make the new number 219.

4. Determine how many times 23 can go into 219.
- 23 goes into 219 nine times because [tex]\(23 \times 9 = 207\)[/tex], which is less than 219.
- Write 9 above the 9 in 449.

5. Subtract 207 from 219.
- [tex]\(219 - 207 = 12\)[/tex].
- Write 12 below 219.

So, the division is done, and we find that:
- The quotient is 19.
- The remainder is 12.

In conclusion, [tex]\( 449 \div 23 = 19 \text{ with a remainder of } 12 \)[/tex].