Discover the best answers at Westonci.ca, where experts share their insights and knowledge with you. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
Let's break down the combustion reaction of butane step-by-step to determine the number of each type of atom on both sides of the equation:
The given balanced equation is:
[tex]\[ 2 C_4H_{10} + 13 O_2 \rightarrow 8 CO_2 + 10 H_2O \][/tex]
First, we need to identify the number of each type of atom on the reactant side and the product side:
### Reactant Side:
1. Carbon (C):
- In [tex]\(2 C_4H_{10}\)[/tex]:
- Each [tex]\(C_4H_{10}\)[/tex] molecule contains 4 carbon atoms.
- Therefore, [tex]\(2 C_4H_{10}\)[/tex] contains [tex]\(2 \times 4 = 8\)[/tex] carbon atoms.
2. Oxygen (O):
- In [tex]\(13 O_2\)[/tex]:
- Each [tex]\(O_2\)[/tex] molecule contains 2 oxygen atoms.
- Therefore, [tex]\(13 O_2\)[/tex] contains [tex]\(13 \times 2 = 26\)[/tex] oxygen atoms.
3. Hydrogen (H):
- In [tex]\(2 C_4H_{10}\)[/tex]:
- Each [tex]\(C_4H_{10}\)[/tex] molecule contains 10 hydrogen atoms.
- Therefore, [tex]\(2 C_4H_{10}\)[/tex] contains [tex]\(2 \times 10 = 20\)[/tex] hydrogen atoms.
### Product Side:
1. Carbon (C):
- In [tex]\(8 CO_2\)[/tex]:
- Each [tex]\(CO_2\)[/tex] molecule contains 1 carbon atom.
- Therefore, [tex]\(8 CO_2\)[/tex] contains [tex]\(8 \times 1 = 8\)[/tex] carbon atoms.
2. Oxygen (O):
- In [tex]\(8 CO_2\)[/tex]:
- Each [tex]\(CO_2\)[/tex] molecule contains 2 oxygen atoms.
- Therefore, [tex]\(8 CO_2\)[/tex] contains [tex]\(8 \times 2 = 16\)[/tex] oxygen atoms.
- In [tex]\(10 H_2O\)[/tex]:
- Each [tex]\(H_2O\)[/tex] molecule contains 1 oxygen atom.
- Therefore, [tex]\(10 H_2O\)[/tex] contains [tex]\(10 \times 1 = 10\)[/tex] oxygen atoms.
- Adding oxygen atoms from both products:
- Total oxygen atoms = [tex]\(16 + 10 = 26\)[/tex] oxygen atoms.
3. Hydrogen (H):
- In [tex]\(10 H_2O\)[/tex]:
- Each [tex]\(H_2O\)[/tex] molecule contains 2 hydrogen atoms.
- Therefore, [tex]\(10 H_2O\)[/tex] contains [tex]\(10 \times 2 = 20\)[/tex] hydrogen atoms.
So, the equation is balanced because it has:
- [tex]\(\boxed{8}\)[/tex] atoms of carbon (C) on each side,
- [tex]\(\boxed{26}\)[/tex] atoms of oxygen (O) on each side, and
- [tex]\(\boxed{20}\)[/tex] atoms of hydrogen (H) on each side.
The given balanced equation is:
[tex]\[ 2 C_4H_{10} + 13 O_2 \rightarrow 8 CO_2 + 10 H_2O \][/tex]
First, we need to identify the number of each type of atom on the reactant side and the product side:
### Reactant Side:
1. Carbon (C):
- In [tex]\(2 C_4H_{10}\)[/tex]:
- Each [tex]\(C_4H_{10}\)[/tex] molecule contains 4 carbon atoms.
- Therefore, [tex]\(2 C_4H_{10}\)[/tex] contains [tex]\(2 \times 4 = 8\)[/tex] carbon atoms.
2. Oxygen (O):
- In [tex]\(13 O_2\)[/tex]:
- Each [tex]\(O_2\)[/tex] molecule contains 2 oxygen atoms.
- Therefore, [tex]\(13 O_2\)[/tex] contains [tex]\(13 \times 2 = 26\)[/tex] oxygen atoms.
3. Hydrogen (H):
- In [tex]\(2 C_4H_{10}\)[/tex]:
- Each [tex]\(C_4H_{10}\)[/tex] molecule contains 10 hydrogen atoms.
- Therefore, [tex]\(2 C_4H_{10}\)[/tex] contains [tex]\(2 \times 10 = 20\)[/tex] hydrogen atoms.
### Product Side:
1. Carbon (C):
- In [tex]\(8 CO_2\)[/tex]:
- Each [tex]\(CO_2\)[/tex] molecule contains 1 carbon atom.
- Therefore, [tex]\(8 CO_2\)[/tex] contains [tex]\(8 \times 1 = 8\)[/tex] carbon atoms.
2. Oxygen (O):
- In [tex]\(8 CO_2\)[/tex]:
- Each [tex]\(CO_2\)[/tex] molecule contains 2 oxygen atoms.
- Therefore, [tex]\(8 CO_2\)[/tex] contains [tex]\(8 \times 2 = 16\)[/tex] oxygen atoms.
- In [tex]\(10 H_2O\)[/tex]:
- Each [tex]\(H_2O\)[/tex] molecule contains 1 oxygen atom.
- Therefore, [tex]\(10 H_2O\)[/tex] contains [tex]\(10 \times 1 = 10\)[/tex] oxygen atoms.
- Adding oxygen atoms from both products:
- Total oxygen atoms = [tex]\(16 + 10 = 26\)[/tex] oxygen atoms.
3. Hydrogen (H):
- In [tex]\(10 H_2O\)[/tex]:
- Each [tex]\(H_2O\)[/tex] molecule contains 2 hydrogen atoms.
- Therefore, [tex]\(10 H_2O\)[/tex] contains [tex]\(10 \times 2 = 20\)[/tex] hydrogen atoms.
So, the equation is balanced because it has:
- [tex]\(\boxed{8}\)[/tex] atoms of carbon (C) on each side,
- [tex]\(\boxed{26}\)[/tex] atoms of oxygen (O) on each side, and
- [tex]\(\boxed{20}\)[/tex] atoms of hydrogen (H) on each side.
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.
