Explore Westonci.ca, the top Q&A platform where your questions are answered by professionals and enthusiasts alike. Join our platform to get reliable answers to your questions from a knowledgeable community of experts. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
Let's solve the given equation step-by-step:
1. The given equation is [tex]\(14.3p - 32.24 = 127.92\)[/tex].
2. To isolate the term with [tex]\(p\)[/tex], we need to eliminate the constant term on the left side of the equation. We do this by adding 32.24 to both sides of the equation:
[tex]\[ 14.3p - 32.24 + 32.24 = 127.92 + 32.24 \][/tex]
3. Simplifying both sides, we have:
[tex]\[ 14.3p = 160.16 \][/tex]
4. Next, we want to solve for [tex]\(p\)[/tex] by isolating it. We do this by dividing both sides of the equation by 14.3:
[tex]\[ \frac{14.3p}{14.3} = \frac{160.16}{14.3} \][/tex]
5. Simplifying the fractions, we get:
[tex]\[ p = 11.2 \][/tex]
Hence, the value of [tex]\(p\)[/tex] is [tex]\(\boxed{11.2}\)[/tex].
1. The given equation is [tex]\(14.3p - 32.24 = 127.92\)[/tex].
2. To isolate the term with [tex]\(p\)[/tex], we need to eliminate the constant term on the left side of the equation. We do this by adding 32.24 to both sides of the equation:
[tex]\[ 14.3p - 32.24 + 32.24 = 127.92 + 32.24 \][/tex]
3. Simplifying both sides, we have:
[tex]\[ 14.3p = 160.16 \][/tex]
4. Next, we want to solve for [tex]\(p\)[/tex] by isolating it. We do this by dividing both sides of the equation by 14.3:
[tex]\[ \frac{14.3p}{14.3} = \frac{160.16}{14.3} \][/tex]
5. Simplifying the fractions, we get:
[tex]\[ p = 11.2 \][/tex]
Hence, the value of [tex]\(p\)[/tex] is [tex]\(\boxed{11.2}\)[/tex].
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.