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[tex]\[ 3\left(2^{2t-5}\right)-4=10 \][/tex]

1. Simplify:
[tex]\[ 3\left(2^{2t-5}\right)-4=10 \][/tex]
[tex]\[ 3\left(2^{2t-5}\right)=14 \][/tex]
[tex]\[ 2^{2t-5}=\frac{14}{3} \][/tex]

2. Take the log of each side:
[tex]\[ \log \left(2^{2t-5}\right)=\log \left(\frac{14}{3}\right) \][/tex]

3. Solve for [tex]\( t \)[/tex]:
[tex]\[ 2t-5 = \log_2 \left(\frac{14}{3}\right) \][/tex]
[tex]\[ t \approx 3.625 \][/tex]


Sagot :

To solve the equation [tex]\(3\left(2^{2t-5}\right) - 4 = 10\)[/tex], let's follow these steps in order:

1. Simplify the equation by isolating the exponential term:
[tex]\[ 3\left(2^{2t - 5}\right) - 4 + 4 = 10 + 4 \][/tex]
Simplified:
[tex]\[ 3\left(2^{2t - 5}\right) = 14 \][/tex]

2. Divide both sides by 3 to further isolate the exponential term:
[tex]\[ \left(2^{2t - 5}\right) = \frac{14}{3} \][/tex]

3. Take the logarithm of each side to decompose the exponent:
[tex]\[ \log \left(2^{2t - 5}\right) = \log \left(\frac{14}{3}\right) \][/tex]

4. Use the power rule of logarithms (i.e., [tex]\( \log(a^b) = b \log(a) \)[/tex]) to bring down the exponent:
[tex]\[ (2t - 5) \log(2) = \log \left(\frac{14}{3}\right) \][/tex]

5. Solve for [tex]\( t \)[/tex] by isolating it step by step:
[tex]\[ 2t - 5 = \frac{\log \left(\frac{14}{3}\right)}{\log(2)} \][/tex]
Simplify further:
[tex]\[ 2t = \frac{\log \left(\frac{14}{3}\right)}{\log(2)} + 5 \][/tex]
Finally:
[tex]\[ t = \frac{\frac{\log \left(\frac{14}{3}\right)}{\log(2)} + 5}{2} \][/tex]

Given that we have the numerical solution involved in detailed logarithm calculations, the intermediate result for [tex]\( \frac{\log \left(\frac{14}{3}\right)}{\log(2)}\)[/tex] is approximately 2.722, and the final value of [tex]\( t \)[/tex] is approximately 3.611. Therefore,

Thus, following all steps correctly, we can approximate:
[tex]\[ t \approx 3.611 \][/tex]