Looking for trustworthy answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
To determine which half-reaction describes the reduction process taking place, we first need to understand what reduction means in the context of a redox (reduction-oxidation) reaction. Reduction refers to the gain of electrons by a species.
Given the redox reaction:
[tex]\[ Mg (s) + Fe^{2+} (aq) \longrightarrow Mg^{2+} (aq) + Fe (s) \][/tex]
We break it down into oxidation and reduction half-reactions:
1. Oxidation: Magnesium metal [tex]\( (Mg) \)[/tex] is oxidized as it loses electrons:
[tex]\[ Mg (s) \longrightarrow Mg^{2+} (aq) + 2e^{-} \][/tex]
2. Reduction: Iron(II) ions [tex]\( (Fe^{2+}) \)[/tex] are reduced as they gain electrons:
[tex]\[ Fe^{2+} (aq) + 2e^{-} \longrightarrow Fe (s) \][/tex]
Now we will examine each provided option to determine which one correctly represents the reduction half-reaction:
1. [tex]\( Fe^{2+} (aq) + 2e^{-} \longrightarrow Fe (s) \)[/tex]
- This equation shows iron(II) ions gaining 2 electrons to form solid iron, a reduction process.
2. [tex]\( Mg (s) \longrightarrow Mg^{2+} (aq) + 2e^{-} \)[/tex]
- This equation shows magnesium losing 2 electrons, indicating oxidation, not reduction.
3. [tex]\( Fe^{2+} (aq) \longrightarrow Fe (s) + 2e^{-} \)[/tex]
- This equation incorrectly shows iron(II) ions losing electrons to form solid iron, which is not a reduction half-reaction.
4. [tex]\( Mg (s) + 2e^{-} \longrightarrow Mg^{2+} (aq) \)[/tex]
- This equation incorrectly shows magnesium gaining electrons to form magnesium ions, contrary to the actual process which is oxidation.
Considering the correct reduction half-reaction:
[tex]\[ Fe^{2+} (aq) + 2e^{-} \longrightarrow Fe (s) \][/tex]
Therefore, the correct half-reaction that describes the reduction taking place is:
[tex]\[ \boxed{Fe^{2+} (aq) + 2e^{-} \longrightarrow Fe (s)} \][/tex]
Given the redox reaction:
[tex]\[ Mg (s) + Fe^{2+} (aq) \longrightarrow Mg^{2+} (aq) + Fe (s) \][/tex]
We break it down into oxidation and reduction half-reactions:
1. Oxidation: Magnesium metal [tex]\( (Mg) \)[/tex] is oxidized as it loses electrons:
[tex]\[ Mg (s) \longrightarrow Mg^{2+} (aq) + 2e^{-} \][/tex]
2. Reduction: Iron(II) ions [tex]\( (Fe^{2+}) \)[/tex] are reduced as they gain electrons:
[tex]\[ Fe^{2+} (aq) + 2e^{-} \longrightarrow Fe (s) \][/tex]
Now we will examine each provided option to determine which one correctly represents the reduction half-reaction:
1. [tex]\( Fe^{2+} (aq) + 2e^{-} \longrightarrow Fe (s) \)[/tex]
- This equation shows iron(II) ions gaining 2 electrons to form solid iron, a reduction process.
2. [tex]\( Mg (s) \longrightarrow Mg^{2+} (aq) + 2e^{-} \)[/tex]
- This equation shows magnesium losing 2 electrons, indicating oxidation, not reduction.
3. [tex]\( Fe^{2+} (aq) \longrightarrow Fe (s) + 2e^{-} \)[/tex]
- This equation incorrectly shows iron(II) ions losing electrons to form solid iron, which is not a reduction half-reaction.
4. [tex]\( Mg (s) + 2e^{-} \longrightarrow Mg^{2+} (aq) \)[/tex]
- This equation incorrectly shows magnesium gaining electrons to form magnesium ions, contrary to the actual process which is oxidation.
Considering the correct reduction half-reaction:
[tex]\[ Fe^{2+} (aq) + 2e^{-} \longrightarrow Fe (s) \][/tex]
Therefore, the correct half-reaction that describes the reduction taking place is:
[tex]\[ \boxed{Fe^{2+} (aq) + 2e^{-} \longrightarrow Fe (s)} \][/tex]
Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.