Answered

Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Our platform offers a seamless experience for finding reliable answers from a network of experienced professionals. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

What is the final, balanced equation that is formed by combining these two half-reactions?

[tex]\[
\begin{array}{l}
Cu \longrightarrow Cu^{2+} + 2e^{-} \\
NO_3^{-} + 2e^{-} + 2H^{+} \longrightarrow NO_2^{-} + H_2O
\end{array}
\][/tex]

A. [tex]\(Cu + NO_3^{-} + 2H^{+} \longrightarrow Cu^{2+} + NO_2^{-} + H_2O\)[/tex]

B. [tex]\(Cu + NO_3^{-} + 2H^{+} \longrightarrow Cu^{2+} + NO_2^{-} + 2H_2O\)[/tex]

Sagot :

GinnyAnswer
To find the final, balanced equation formed by combining the two given half-reactions, we need to follow a series of steps to ensure both mass and charge are balanced. Let's look at the given half-reactions again:

1.
[tex]\[ Cu \rightarrow Cu^{2+} + 2e^- \][/tex]

2.
[tex]\[ NO_3^- + 2e^- + 2H^+ \rightarrow NO_2^- + H_2O \][/tex]

Step-by-Step Solution:

### Step 1: Identify the Half-Reactions
The two half-reactions are:
- Oxidation half-reaction (copper losing electrons):
[tex]\[ Cu \rightarrow Cu^{2+} + 2e^- \][/tex]
- Reduction half-reaction (nitrate gaining electrons):
[tex]\[ NO_3^- + 2e^- + 2H^+ \rightarrow NO_2^- + H_2O \][/tex]

### Step 2: Balance the Electrons
Each half-reaction involves the transfer of 2 electrons. Since the number of electrons lost in the oxidation half-reaction is equal to the number of electrons gained in the reduction half-reaction, we can combine them directly.

### Step 3: Add the Half-Reactions Together
Combine the two half-reactions, ensuring that the electrons cancel out:
[tex]\[ Cu \rightarrow Cu^{2+} + 2e^- \][/tex]
[tex]\[ NO_3^- + 2e^- + 2H^+ \rightarrow NO_2^- + H_2O \][/tex]

Adding these together:
[tex]\[ Cu + NO_3^- + 2H^+ \rightarrow Cu^{2+} + NO_2^- + H_2O \][/tex]

### Step 4: Verify the Balance
- Atoms:
- Copper (Cu): 1 atom on each side.
- Nitrate (NO3-): 1 nitrogen atom on each side.
- Hydrogen (H+): 2 atoms on the left, and in the product [tex]\( H_2O \)[/tex] (2 H atoms).
- Oxygen (O): 3 atoms from [tex]\( NO_3^- \)[/tex] on the left, with 1 oxygen in [tex]\( NO_2^- \)[/tex] and another 1 in [tex]\( H_2O \)[/tex] on the right.

- Charge:
- Left side: No net charge because [tex]\( Cu \)[/tex] is neutral, [tex]\( NO_3^- \)[/tex] contributes -1, and [tex]\( 2H^+ \)[/tex] contributes +2, making the total charge +1.
- Right side: [tex]\( Cu^{2+} \)[/tex] contributes +2, [tex]\( NO_2^- \)[/tex] contributes -1, making the total charge also +1.

Both mass and charge are balanced.

### Final Balanced Equation:
[tex]\[ Cu + NO_3^- + 2H^+ \rightarrow Cu^{2+} + NO_2^- + H_2O \][/tex]

Therefore, the final balanced equation you proposed is:
[tex]\[ Cu + NO_3^- + 2H^+ \longrightarrow Cu^{2+} + NO_2^- + H_2O \][/tex]
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.