Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Get immediate and reliable solutions to your questions from a community of experienced experts on our Q&A platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
To determine which half-reaction correctly describes the oxidation taking place in the given reaction:
[tex]\[ \text{Zn (s)} + \text{Cu}^{2+} \text{(aq)} \longrightarrow \text{Zn}^{2+} \text{(aq)} + \text{Cu (s)} \][/tex]
We need to understand what oxidation is. Oxidation is the process where a species loses electrons, resulting in an increase in its oxidation state.
Here are the steps to find the correct oxidative half-reaction:
1. Identify the species involved:
- Zinc ([tex]\(\text{Zn}\)[/tex]) in solid form.
- Copper ion ([tex]\(\text{Cu}^{2+}\)[/tex]) in aqueous form.
2. Determine the oxidation state changes:
- For Zinc: Initially, Zinc is in the solid state ([tex]\( \text{Zn} \)[/tex]), which has an oxidation state of [tex]\(0\)[/tex]. After the reaction, it becomes [tex]\(\text{Zn}^{2+}\)[/tex] (aqueous), which has an oxidation state of [tex]\(+2\)[/tex].
- For Copper: Initially, Copper is a [tex]\( \text{Cu}^{2+} \)[/tex] ion (aqueous) with an oxidation state of [tex]\(+2\)[/tex]. After the reaction, Copper is in the solid form ([tex]\( \text{Cu} \)[/tex]), which has an oxidation state of [tex]\(0\)[/tex].
3. Identify the species undergoing oxidation:
- Zinc ([tex]\(\text{Zn}\)[/tex]) is going from an oxidation state of [tex]\(0\)[/tex] to [tex]\(+2\)[/tex]. This is an increase in the oxidation state, indicating oxidation.
4. Write the oxidation half-reaction:
- The oxidation half-reaction will indicate the species losing electrons. For Zinc:
[tex]\[ \text{Zn} (s) \longrightarrow \text{Zn}^{2+} \text{(aq)} + 2e^- \][/tex]
This equation shows that Zinc loses two electrons (indicated by [tex]\(2e^-\)[/tex]) when it oxidizes from a neutral atom to a [tex]\( \text{Zn}^{2+} \)[/tex] ion.
Therefore, the correct half-reaction describing the oxidation that is taking place is:
[tex]\[ \text{Zn} (s) \longrightarrow \text{Zn}^{2+} \text{(aq)} + 2e^- \][/tex]
So, the answer is:
[tex]\[ \boxed{\text{Zn (s) } \longrightarrow \text{Zn}^{2+} \text{(aq)} + 2e^-} \][/tex]
[tex]\[ \text{Zn (s)} + \text{Cu}^{2+} \text{(aq)} \longrightarrow \text{Zn}^{2+} \text{(aq)} + \text{Cu (s)} \][/tex]
We need to understand what oxidation is. Oxidation is the process where a species loses electrons, resulting in an increase in its oxidation state.
Here are the steps to find the correct oxidative half-reaction:
1. Identify the species involved:
- Zinc ([tex]\(\text{Zn}\)[/tex]) in solid form.
- Copper ion ([tex]\(\text{Cu}^{2+}\)[/tex]) in aqueous form.
2. Determine the oxidation state changes:
- For Zinc: Initially, Zinc is in the solid state ([tex]\( \text{Zn} \)[/tex]), which has an oxidation state of [tex]\(0\)[/tex]. After the reaction, it becomes [tex]\(\text{Zn}^{2+}\)[/tex] (aqueous), which has an oxidation state of [tex]\(+2\)[/tex].
- For Copper: Initially, Copper is a [tex]\( \text{Cu}^{2+} \)[/tex] ion (aqueous) with an oxidation state of [tex]\(+2\)[/tex]. After the reaction, Copper is in the solid form ([tex]\( \text{Cu} \)[/tex]), which has an oxidation state of [tex]\(0\)[/tex].
3. Identify the species undergoing oxidation:
- Zinc ([tex]\(\text{Zn}\)[/tex]) is going from an oxidation state of [tex]\(0\)[/tex] to [tex]\(+2\)[/tex]. This is an increase in the oxidation state, indicating oxidation.
4. Write the oxidation half-reaction:
- The oxidation half-reaction will indicate the species losing electrons. For Zinc:
[tex]\[ \text{Zn} (s) \longrightarrow \text{Zn}^{2+} \text{(aq)} + 2e^- \][/tex]
This equation shows that Zinc loses two electrons (indicated by [tex]\(2e^-\)[/tex]) when it oxidizes from a neutral atom to a [tex]\( \text{Zn}^{2+} \)[/tex] ion.
Therefore, the correct half-reaction describing the oxidation that is taking place is:
[tex]\[ \text{Zn} (s) \longrightarrow \text{Zn}^{2+} \text{(aq)} + 2e^- \][/tex]
So, the answer is:
[tex]\[ \boxed{\text{Zn (s) } \longrightarrow \text{Zn}^{2+} \text{(aq)} + 2e^-} \][/tex]
Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.