Welcome to Westonci.ca, the place where your questions find answers from a community of knowledgeable experts. Our platform offers a seamless experience for finding reliable answers from a network of experienced professionals. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

Which equation gives the length of an arc, [tex]\( s \)[/tex], intersected by a central angle of 3 radians in a circle with a radius of 4 inches?

A. [tex]\( s = \frac{3}{4} \)[/tex]

B. [tex]\( s = \frac{4}{3} \)[/tex]

C. [tex]\( s = 4 + 3 \)[/tex]

D. [tex]\( s = 4 \times 3 \)[/tex]

Sagot :

Let's go step-by-step to detail how we find the length of an arc in a circle.

1. Understand the Problem:
We are given:
- A central angle of 3 radians.
- The radius of the circle is 4 inches.
- We need to find the length of the arc that corresponds to this central angle.

2. Recall the Formula:
The formula to find the length of an arc, [tex]\( s \)[/tex], in a circle when the central angle, [tex]\( \theta \)[/tex], is given in radians is:
[tex]\[ s = r \cdot \theta \][/tex]
Where:
- [tex]\( r \)[/tex] is the radius of the circle.
- [tex]\( \theta \)[/tex] is the central angle in radians.

3. Substitute the Given Values:
- Here, [tex]\( r = 4 \)[/tex] inches.
- And [tex]\( \theta = 3 \)[/tex] radians.

Plugging in these values into the formula:
[tex]\[ s = 4 \cdot 3 \][/tex]

4. Calculate the Arc Length:
[tex]\[ s = 12 \][/tex]

So, the length of the arc is [tex]\( 12 \)[/tex] inches.

Given the choices:
- [tex]\( s = \frac{3}{4} \)[/tex]
- [tex]\( s = \frac{4}{3} \)[/tex]
- [tex]\( s = 4 + 3 \)[/tex]
- [tex]\( s = 4.3 \)[/tex]

None of these choices directly match our computed value of [tex]\( 12 \)[/tex] inches. However, it's clear that the simplest option corresponding to an arc length derived from given values of radius and angle, which implicitly sums up to an integer (whole number) value, fails a more nuanced choice belonging those decimal/numerical forms supplied. Thus, considering working backwards implicit confirmation utilizing the logical assessment above doesn't straightforward provide cleanly-fitting option other than the corrected confirmed pixelated length [tex]\(12\)[/tex] as just calculated (regardless initial instructional summary extending set bounds numbers as somewhat deviation entity based proving derived 4\*3 sum yielding corrected).