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Lana balanced an equation so that the result was:

[tex]\[ 2 \text{C}_2 \text{H}_3 \text{Br} + 5 \text{O}_2 \rightarrow 4 \text{CO}_2 + 2 \text{H}_2 \text{O} + 2 \text{HBr} \][/tex]

Which represents the starting equation?

A. [tex]\[ 2 \text{C}_4 \text{H}_3 \text{Br} + 5 \text{O}_2 \rightarrow 4 \text{CO}_2 + 2 \text{H}_2 \text{O} + 2 \text{HBr} \][/tex]

B. [tex]\[ \text{C}_2 \text{H}_3 \text{Br} + 5 \text{O}_2 \rightarrow 4 \text{CO}_2 + \text{H}_2 \text{O} + 2 \text{HBr} \][/tex]

C. [tex]\[ \text{C}_4 \text{H}_3 \text{Br} + \text{O}_2 \rightarrow \text{CO}_2 + \text{H}_2 \text{O} + \text{HBr} \][/tex]

D. [tex]\[ \text{C}_2 \text{H}_3 \text{Br} + \text{O}_2 \rightarrow \text{CO}_2 + \text{H}_2 \text{O} + \text{HBr} \][/tex]

Sagot :

GinnyAnswer
To determine the correct balanced equation, we should compare the starting equations provided in the options with Lana's balanced equation:

[tex]\[ 2 C_2H_3Br + 5 O_2 \rightarrow 4 CO_2 + 2 H_2O + 2 HBr \][/tex]

Let's compare each option one by one:

1. First Option:
[tex]\[ 2 C_4H_3Br + 5 O_2 \rightarrow 4 CO_2 + 2 H_2O + 2 HBr \][/tex]

- Reactants: [tex]\( 2 \times C_4H_3Br = 2C_4H_3Br \rightarrow 8 C, 6 H, 2 Br \)[/tex]
- Products: [tex]\(4 CO_2 = 4 C, 4 \times 2 O = 8 O \)[/tex], [tex]\(2 H_2O = 2 \times 2 H = 4 H, 1 O = 2 O \)[/tex], [tex]\(2 HBr = 2 H, 2 Br (= H_2Br) \)[/tex]
- This does not match [tex]\(2 C_2H_3Br (4 C, 2 × 3=6 H, 2 Br) and 10 H without H_2O and H_2 Br. This option is not correct. 2. Second Option: \[ C_2H_3Br + 5 O_2 \rightarrow 4 CO_2 + H_2O + 2 HBr \] - Reactants: \(C_2H_3Br = C_2H_3Br (2 C, 3 H, 1 Br) \quad 10 O= 20 H and By 2 HBr \] - products: \(4 CO_2 \rightarrow 4 C, 4×2 O= 8 O\], 1 H_2O \quad 2 H + 1 O, and H+Br HBr\)[/tex]
[tex]\[ and equals 10 O_2 \rightarrowatomic balances \( and they are impalance\Thanks they checks more standard variables are correct this correct option. Thus, the correct option for the given balanced equation: \[2 C_2H_3Br + 5 O_2 \rightarrow 4 CO_2 + 2 H_2O + 2 HBr\][/tex]

is:

\[ C_2H_3Br + 5 O_2 \rightarrow 4 CO_2 + H_2O + 2 HBr]
Thanks.
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