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In [tex]$\triangle ABC$[/tex], [tex]$AB = x$[/tex], [tex]$BC = y$[/tex], and [tex]$CA = 2x$[/tex]. A similarity transformation with a scale factor of 0.5 maps [tex]$\triangle ABC$[/tex] to [tex]$\triangle MNO$[/tex], such that vertices [tex]$M$[/tex], [tex]$N$[/tex], and [tex]$O$[/tex] correspond to [tex]$A$[/tex], [tex]$B$[/tex], and [tex]$C$[/tex], respectively. If [tex]$OM = 5$[/tex], what is [tex]$AB$[/tex]?

A. [tex]$AB = 2.5$[/tex]

B. [tex]$AB = 10$[/tex]

C. [tex]$AB = 5$[/tex]

D. [tex]$AB = 1.25$[/tex]

E. [tex]$AB = 2$[/tex]

Sagot :

To solve the problem, let's analyze the given information step-by-step meticulously:

1. Similarity Transformation Concept: We know that a similarity transformation keeps the shapes of triangles the same but changes their sizes by a specific ratio, known as the scale factor.

2. Scale Factor: The problem states that a similarity transformation with a scale factor of [tex]\(0.5\)[/tex] (or [tex]\(\frac{1}{2}\)[/tex]) is applied to [tex]\(\triangle ABC\)[/tex], resulting in [tex]\(\triangle MNO\)[/tex], with vertices [tex]\(M\)[/tex], [tex]\(N\)[/tex], and [tex]\(O\)[/tex] corresponding to [tex]\(A\)[/tex], [tex]\(B\)[/tex], and [tex]\(C\)[/tex] respectively.

3. Length of [tex]\(OM\)[/tex]: We are provided with [tex]\(OM = 5\)[/tex], which is the image of [tex]\(CA\)[/tex] after the transformation.

4. Relationship between Original and Transformed Lengths:
[tex]\[ OM = \text{scale factor} \times CA \quad \text{or} \quad 5 = 0.5 \times CA \][/tex]

5. Solving for [tex]\(CA\)[/tex]: To find [tex]\(CA\)[/tex], we solve the above equation:
[tex]\[ 5 = 0.5 \times CA \][/tex]
[tex]\[ CA = \frac{5}{0.5} = 10 \][/tex]

6. Given Relationship [tex]\(CA = 2x\)[/tex]: In the original [tex]\(\triangle ABC\)[/tex], it is given that [tex]\(CA = 2x\)[/tex]. We already found that [tex]\(CA = 10\)[/tex].
[tex]\[ 2x = 10 \][/tex]

7. Solving for [tex]\(x\)[/tex]: We now solve for [tex]\(x\)[/tex]:
[tex]\[ x = \frac{10}{2} = 5 \][/tex]

8. Length of [tex]\(AB\)[/tex]: Recall from the given notation that [tex]\(AB = x\)[/tex]. Therefore, substituting [tex]\(x\)[/tex],
[tex]\[ AB = 5 \][/tex]

Thus, the correct answer is [tex]\(C. \, AB = 5\)[/tex].