Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Explore our Q&A platform to find in-depth answers from a wide range of experts in different fields. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
To complete the expression so it forms a perfect-square trinomial, we need to follow the process of completing the square.
## Part 1: Completing [tex]\( x^2 - 5x + \cdots \)[/tex]
1. Start with the given quadratic expression: [tex]\( x^2 - 5x \)[/tex].
2. Take the coefficient of [tex]\( x \)[/tex], which is [tex]\( -5 \)[/tex].
3. Divide this coefficient by 2: [tex]\( \frac{-5}{2} = -\frac{5}{2} \)[/tex].
4. Square the result from step 3: [tex]\((-\frac{5}{2})^2 = \frac{25}{4} \)[/tex].
5. Add this square to the quadratic expression to form a perfect-square trinomial: [tex]\( x^2 - 5x + \frac{25}{4} \)[/tex].
So, the completed expression is [tex]\( x^2 - 5x + \frac{25}{4} \)[/tex].
## Part 2: Completing [tex]\( x^2 + \square x + 49 \)[/tex]
Next, we need to complete the square for [tex]\( x^2 + kx + 49 \)[/tex] by finding the appropriate coefficient [tex]\( k \)[/tex]:
1. Let’s denote the coefficient of [tex]\( x \)[/tex] by [tex]\( k \)[/tex].
2. Since the constant term [tex]\( 49 \)[/tex] is a perfect square, this term is equivalent to [tex]\( 7^2 \)[/tex].
3. To form a perfect square trinomial of the form [tex]\( (x + c)^2 \)[/tex], [tex]\( c \)[/tex] would need to be added and then squared to yield the constant.
4. Set the equation for [tex]\( c \)[/tex]: [tex]\( \left(\frac{k}{2}\right)^2 = 49 \)[/tex].
5. Solving for [tex]\( k \)[/tex]:
- [tex]\(\left(\frac{k}{2}\right)^2 = 49\)[/tex],
- [tex]\(\frac{k^2}{4} = 49\)[/tex],
- [tex]\( k^2 = 196 \)[/tex],
- [tex]\( k = \pm 14 \)[/tex].
So the coefficient [tex]\( k \)[/tex] found is [tex]\( \pm 14 \)[/tex].
Therefore, the completed perfect-square trinomial is either [tex]\( x^2 + 14x + 49 \)[/tex] or [tex]\( x^2 - 14x + 49 \)[/tex].
### Final Answers:
1. [tex]\( x^2 - 5x + \frac{25}{4} \)[/tex]
2. [tex]\( x^2 + 14x + 49 \)[/tex] or [tex]\( x^2 - 14x + 49 \)[/tex]
## Part 1: Completing [tex]\( x^2 - 5x + \cdots \)[/tex]
1. Start with the given quadratic expression: [tex]\( x^2 - 5x \)[/tex].
2. Take the coefficient of [tex]\( x \)[/tex], which is [tex]\( -5 \)[/tex].
3. Divide this coefficient by 2: [tex]\( \frac{-5}{2} = -\frac{5}{2} \)[/tex].
4. Square the result from step 3: [tex]\((-\frac{5}{2})^2 = \frac{25}{4} \)[/tex].
5. Add this square to the quadratic expression to form a perfect-square trinomial: [tex]\( x^2 - 5x + \frac{25}{4} \)[/tex].
So, the completed expression is [tex]\( x^2 - 5x + \frac{25}{4} \)[/tex].
## Part 2: Completing [tex]\( x^2 + \square x + 49 \)[/tex]
Next, we need to complete the square for [tex]\( x^2 + kx + 49 \)[/tex] by finding the appropriate coefficient [tex]\( k \)[/tex]:
1. Let’s denote the coefficient of [tex]\( x \)[/tex] by [tex]\( k \)[/tex].
2. Since the constant term [tex]\( 49 \)[/tex] is a perfect square, this term is equivalent to [tex]\( 7^2 \)[/tex].
3. To form a perfect square trinomial of the form [tex]\( (x + c)^2 \)[/tex], [tex]\( c \)[/tex] would need to be added and then squared to yield the constant.
4. Set the equation for [tex]\( c \)[/tex]: [tex]\( \left(\frac{k}{2}\right)^2 = 49 \)[/tex].
5. Solving for [tex]\( k \)[/tex]:
- [tex]\(\left(\frac{k}{2}\right)^2 = 49\)[/tex],
- [tex]\(\frac{k^2}{4} = 49\)[/tex],
- [tex]\( k^2 = 196 \)[/tex],
- [tex]\( k = \pm 14 \)[/tex].
So the coefficient [tex]\( k \)[/tex] found is [tex]\( \pm 14 \)[/tex].
Therefore, the completed perfect-square trinomial is either [tex]\( x^2 + 14x + 49 \)[/tex] or [tex]\( x^2 - 14x + 49 \)[/tex].
### Final Answers:
1. [tex]\( x^2 - 5x + \frac{25}{4} \)[/tex]
2. [tex]\( x^2 + 14x + 49 \)[/tex] or [tex]\( x^2 - 14x + 49 \)[/tex]
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.