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Given [tex]\((x-1)^2 = 50\)[/tex], select the values of [tex]\(x\)[/tex].

A. [tex]\(x = -49\)[/tex]

B. [tex]\(x = 51\)[/tex]

C. [tex]\(x = 1 + 5\sqrt{2}\)[/tex]

D. [tex]\(x = 1 - 5\sqrt{2}\)[/tex]


Sagot :

Let's solve the equation [tex]\((x-1)^2 = 50\)[/tex] step-by-step to find the correct values for [tex]\( x \)[/tex].

First, we start by expanding the left side of the equation:
[tex]\[ (x - 1)^2 = 50 \][/tex]

To solve this, we need to take the square root of both sides:
[tex]\[ x - 1 = \pm \sqrt{50} \][/tex]

Simplifying [tex]\(\sqrt{50}\)[/tex]:
[tex]\[ \sqrt{50} = \sqrt{25 \cdot 2} = 5\sqrt{2} \][/tex]

Thus, we have two possible equations:
[tex]\[ x - 1 = 5\sqrt{2} \quad \text{or} \quad x - 1 = -5\sqrt{2} \][/tex]

Solving for [tex]\( x \)[/tex] in each case:
[tex]\[ x = 1 + 5\sqrt{2} \quad \text{or} \quad x = 1 - 5\sqrt{2} \][/tex]

So, the solutions for [tex]\( x \)[/tex] are:
[tex]\[ x = 1 + 5\sqrt{2} \quad \text{and} \quad x = 1 - 5\sqrt{2} \][/tex]

Next, let's compare these solutions to the given options:
1. [tex]\( x = -49 \)[/tex]
2. [tex]\( x = 51 \)[/tex]
3. [tex]\( x = 1 + 5\sqrt{2} \)[/tex]
4. [tex]\( x = 1 - 5\sqrt{2} \)[/tex]

We already identified the solutions to be [tex]\( x = 1 + 5\sqrt{2} \)[/tex] and [tex]\( x = 1 - 5\sqrt{2} \)[/tex].

Checking each option:
1. [tex]\( x = -49 \)[/tex]: This is not a solution.
2. [tex]\( x = 51 \)[/tex]: This is not a solution.
3. [tex]\( x = 1 + 5\sqrt{2} \)[/tex]: This is a solution.
4. [tex]\( x = 1 - 5\sqrt{2} \)[/tex]: This is a solution.

Thus, the correct values for [tex]\( x \)[/tex] are:
[tex]\[ x = 1 + 5\sqrt{2} \quad \text{and} \quad x = 1 - 5\sqrt{2} \][/tex]