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Consider [tex]\( 8x^2 - 48x = -104 \)[/tex].

Rewrite the equation so that [tex]\( a = 1 \)[/tex]:

[tex]\[ x^2 + \square x = \square \][/tex]

Sagot :

GinnyAnswer
Certainly! Let's start by simplifying the given quadratic equation:

[tex]\[ 8x^2 - 48x = -104 \][/tex]

Our goal is to rewrite the equation so that [tex]\( a = 1 \)[/tex]. To do this, we need to divide the entire equation by 8.

First, divide each term in the equation by 8:

[tex]\[ \frac{8x^2}{8} - \frac{48x}{8} = \frac{-104}{8} \][/tex]

This simplifies to:

[tex]\[ x^2 - 6x = -13 \][/tex]

So, the equation with [tex]\( a = 1 \)[/tex] can be written as:

[tex]\[ x^2 - 6x = -13 \][/tex]

Hence, the expression filled in would be:

[tex]\[ x^2 - 6x = -13 \][/tex]
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