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Sagot :
To find the electric potential [tex]\( V \)[/tex], we will use the relationship between electric potential energy [tex]\( U \)[/tex], electric charge [tex]\( Q \)[/tex], and electric potential [tex]\( V \)[/tex]:
[tex]\[ V = \frac{U}{Q} \][/tex]
where:
- [tex]\( U \)[/tex] is the electric potential energy,
- [tex]\( Q \)[/tex] is the electric charge, and
- [tex]\( V \)[/tex] is the electric potential.
Given the values:
- Electric potential energy [tex]\( U = 0.027 \)[/tex] Joules,
- Electric charge [tex]\( Q = 4.5 \times 10^{-5} \)[/tex] Coulombs.
We substitute these values into the formula:
[tex]\[ V = \frac{0.027}{4.5 \times 10^{-5}} \][/tex]
Performing the division:
[tex]\[ V = \frac{0.027}{4.5 \times 10^{-5}} = 600 \text{ Volts} \][/tex]
Therefore, the electric potential of the charge is [tex]\( 600 \)[/tex] Volts.
[tex]\[ V = \frac{U}{Q} \][/tex]
where:
- [tex]\( U \)[/tex] is the electric potential energy,
- [tex]\( Q \)[/tex] is the electric charge, and
- [tex]\( V \)[/tex] is the electric potential.
Given the values:
- Electric potential energy [tex]\( U = 0.027 \)[/tex] Joules,
- Electric charge [tex]\( Q = 4.5 \times 10^{-5} \)[/tex] Coulombs.
We substitute these values into the formula:
[tex]\[ V = \frac{0.027}{4.5 \times 10^{-5}} \][/tex]
Performing the division:
[tex]\[ V = \frac{0.027}{4.5 \times 10^{-5}} = 600 \text{ Volts} \][/tex]
Therefore, the electric potential of the charge is [tex]\( 600 \)[/tex] Volts.
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