At Westonci.ca, we make it easy to get the answers you need from a community of informed and experienced contributors. Discover in-depth solutions to your questions from a wide range of experts on our user-friendly Q&A platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
To determine the identity of the unknown element based on its volume and weight, follow these detailed steps:
1. Calculate the density of the unknown element:
[tex]\[ \text{Density} = \frac{\text{Weight}}{\text{Volume}} \][/tex]
Given:
[tex]\[ \text{Weight} = 4.13 \text{ pounds} \][/tex]
[tex]\[ \text{Volume} = 16 \text{ cubic inches} \][/tex]
Plug these values into the formula:
[tex]\[ \text{Density} = \frac{4.13 \text{ lb}}{16 \text{ in}^3} = 0.258125 \text{ lb/in}^3 \][/tex]
2. Compare the calculated density with the known densities from the table:
\begin{tabular}{|l|l|}
\hline Density & [tex]$lb / in ^3$[/tex] \\
\hline Titanium & 0.161 \\
\hline Zinc & 0.258 \\
\hline Iron & 0.284 \\
\hline Silver & 0.379 \\
\hline
\end{tabular}
The calculated density is:
[tex]\[ 0.258125 \text{ lb/in}^3 \][/tex]
3. Identify the element:
- Compare [tex]\(0.258125 \text{ lb/in}^3\)[/tex] with the provided densities.
- The density [tex]\(0.258125 \text{ lb/in}^3\)[/tex] is closest to the density of Zinc, which is [tex]\(0.258 \text{ lb/in}^3\)[/tex].
4. Make the conclusion:
- Since the calculated density (0.258125 lb/in^3) is very close to the density of Zinc (0.258 lb/in^3), the unknown element is most likely Zinc.
The correct answer is:
[tex]\[ \boxed{\text{D. Zinc}} \][/tex]
1. Calculate the density of the unknown element:
[tex]\[ \text{Density} = \frac{\text{Weight}}{\text{Volume}} \][/tex]
Given:
[tex]\[ \text{Weight} = 4.13 \text{ pounds} \][/tex]
[tex]\[ \text{Volume} = 16 \text{ cubic inches} \][/tex]
Plug these values into the formula:
[tex]\[ \text{Density} = \frac{4.13 \text{ lb}}{16 \text{ in}^3} = 0.258125 \text{ lb/in}^3 \][/tex]
2. Compare the calculated density with the known densities from the table:
\begin{tabular}{|l|l|}
\hline Density & [tex]$lb / in ^3$[/tex] \\
\hline Titanium & 0.161 \\
\hline Zinc & 0.258 \\
\hline Iron & 0.284 \\
\hline Silver & 0.379 \\
\hline
\end{tabular}
The calculated density is:
[tex]\[ 0.258125 \text{ lb/in}^3 \][/tex]
3. Identify the element:
- Compare [tex]\(0.258125 \text{ lb/in}^3\)[/tex] with the provided densities.
- The density [tex]\(0.258125 \text{ lb/in}^3\)[/tex] is closest to the density of Zinc, which is [tex]\(0.258 \text{ lb/in}^3\)[/tex].
4. Make the conclusion:
- Since the calculated density (0.258125 lb/in^3) is very close to the density of Zinc (0.258 lb/in^3), the unknown element is most likely Zinc.
The correct answer is:
[tex]\[ \boxed{\text{D. Zinc}} \][/tex]
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.