At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
To determine the height of the cylindrical fuel tank, we start with the volume formula for a cylinder. The volume [tex]\( V \)[/tex] of a cylinder is given by:
[tex]\[ V = \pi r^2 h \][/tex]
where:
- [tex]\( V \)[/tex] is the volume
- [tex]\( r \)[/tex] is the radius of the base of the cylinder
- [tex]\( h \)[/tex] is the height of the cylinder
- [tex]\( \pi \)[/tex] is a constant (approximately 3.14159)
Since [tex]\( r \)[/tex], the radius, is half the diameter [tex]\( d \)[/tex], we can express the radius as:
[tex]\[ r = \frac{d}{2} \][/tex]
Substituting [tex]\( r \)[/tex] into the volume formula, we get:
[tex]\[ V = \pi \left( \frac{d}{2} \right)^2 h \][/tex]
Simplifying inside the parentheses:
[tex]\[ V = \pi \left( \frac{d^2}{4} \right) h \][/tex]
[tex]\[ V = \frac{\pi d^2}{4} h \][/tex]
To isolate [tex]\( h \)[/tex], we solve for [tex]\( h \)[/tex]:
[tex]\[ h = \frac{4V}{\pi d^2} \][/tex]
Examining the provided answer choices:
- A. [tex]\(\frac{2 V}{\pi d^2}\)[/tex]
- B. [tex]\(\frac{4 V}{d^2}\)[/tex]
- C. [tex]\(\frac{V}{\pi d^2}\)[/tex]
- D. [tex]\(\frac{4 V}{\pi d^2}\)[/tex]
- E. [tex]\(\frac{8 V}{\pi d^2}\)[/tex]
We see that the accurate solution for the height [tex]\( h \)[/tex] is:
[tex]\[ h = \frac{4V}{\pi d^2} \][/tex]
Thus, the correct answer is:
[tex]\[ \text{D.} \quad \frac{4 V}{\pi d^2} \][/tex]
[tex]\[ V = \pi r^2 h \][/tex]
where:
- [tex]\( V \)[/tex] is the volume
- [tex]\( r \)[/tex] is the radius of the base of the cylinder
- [tex]\( h \)[/tex] is the height of the cylinder
- [tex]\( \pi \)[/tex] is a constant (approximately 3.14159)
Since [tex]\( r \)[/tex], the radius, is half the diameter [tex]\( d \)[/tex], we can express the radius as:
[tex]\[ r = \frac{d}{2} \][/tex]
Substituting [tex]\( r \)[/tex] into the volume formula, we get:
[tex]\[ V = \pi \left( \frac{d}{2} \right)^2 h \][/tex]
Simplifying inside the parentheses:
[tex]\[ V = \pi \left( \frac{d^2}{4} \right) h \][/tex]
[tex]\[ V = \frac{\pi d^2}{4} h \][/tex]
To isolate [tex]\( h \)[/tex], we solve for [tex]\( h \)[/tex]:
[tex]\[ h = \frac{4V}{\pi d^2} \][/tex]
Examining the provided answer choices:
- A. [tex]\(\frac{2 V}{\pi d^2}\)[/tex]
- B. [tex]\(\frac{4 V}{d^2}\)[/tex]
- C. [tex]\(\frac{V}{\pi d^2}\)[/tex]
- D. [tex]\(\frac{4 V}{\pi d^2}\)[/tex]
- E. [tex]\(\frac{8 V}{\pi d^2}\)[/tex]
We see that the accurate solution for the height [tex]\( h \)[/tex] is:
[tex]\[ h = \frac{4V}{\pi d^2} \][/tex]
Thus, the correct answer is:
[tex]\[ \text{D.} \quad \frac{4 V}{\pi d^2} \][/tex]
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.