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A satellite launch rocket has a cylindrical fuel tank. The fuel tank can hold [tex][tex]$V$[/tex][/tex] cubic meters of fuel. If the tank measures [tex][tex]$d$[/tex][/tex] meters across, what is the height of the tank in meters?

A. [tex]\frac{2 V}{\pi d^2}[/tex]
B. [tex]\frac{4 V}{d^2}[/tex]
C. [tex]\frac{V}{\pi d^2}[/tex]
D. [tex]\frac{4 V}{\pi d^2}[/tex]
E. [tex]\frac{8 V}{\pi d^2}[/tex]


Sagot :

To determine the height of the cylindrical fuel tank, we start with the volume formula for a cylinder. The volume [tex]\( V \)[/tex] of a cylinder is given by:

[tex]\[ V = \pi r^2 h \][/tex]

where:
- [tex]\( V \)[/tex] is the volume
- [tex]\( r \)[/tex] is the radius of the base of the cylinder
- [tex]\( h \)[/tex] is the height of the cylinder
- [tex]\( \pi \)[/tex] is a constant (approximately 3.14159)

Since [tex]\( r \)[/tex], the radius, is half the diameter [tex]\( d \)[/tex], we can express the radius as:

[tex]\[ r = \frac{d}{2} \][/tex]

Substituting [tex]\( r \)[/tex] into the volume formula, we get:

[tex]\[ V = \pi \left( \frac{d}{2} \right)^2 h \][/tex]

Simplifying inside the parentheses:

[tex]\[ V = \pi \left( \frac{d^2}{4} \right) h \][/tex]

[tex]\[ V = \frac{\pi d^2}{4} h \][/tex]

To isolate [tex]\( h \)[/tex], we solve for [tex]\( h \)[/tex]:

[tex]\[ h = \frac{4V}{\pi d^2} \][/tex]

Examining the provided answer choices:
- A. [tex]\(\frac{2 V}{\pi d^2}\)[/tex]
- B. [tex]\(\frac{4 V}{d^2}\)[/tex]
- C. [tex]\(\frac{V}{\pi d^2}\)[/tex]
- D. [tex]\(\frac{4 V}{\pi d^2}\)[/tex]
- E. [tex]\(\frac{8 V}{\pi d^2}\)[/tex]

We see that the accurate solution for the height [tex]\( h \)[/tex] is:

[tex]\[ h = \frac{4V}{\pi d^2} \][/tex]

Thus, the correct answer is:
[tex]\[ \text{D.} \quad \frac{4 V}{\pi d^2} \][/tex]