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1. The equation of the tangent to the circle [tex][tex]$x^2 + y^2 + 4x - 6y - 13 = 0$[/tex][/tex] at the point [tex][tex]$(3, 4)$[/tex][/tex] is:

A. [tex]3x + 4y = 17[/tex]
B. [tex]5x + y = 19[/tex]
C. [tex]2x - 7y = 9[/tex]
D. [tex]5x + 3y = 1[/tex]

Sagot :

To find the equation of the tangent to the circle given by the equation [tex]\( x^2 + y^2 + 4x - 6y - 13 = 0 \)[/tex] at the point [tex]\( (3, 4) \)[/tex], follow these steps:

1. Rewrite the Circle Equation in Standard Form:

The general form of a circle's equation is [tex]\( (x - h)^2 + (y - k)^2 = r^2 \)[/tex]. We need to rewrite the given equation in this form.

[tex]\[ x^2 + 4x + y^2 - 6y - 13 = 0 \][/tex]

Complete the square for [tex]\( x \)[/tex] and [tex]\( y \)[/tex]:

[tex]\[ \begin{aligned} x^2 + 4x &\implies (x + 2)^2 - 4, \\ y^2 - 6y &\implies (y - 3)^2 - 9. \end{aligned} \][/tex]

Thus, the equation becomes:

[tex]\[ (x + 2)^2 - 4 + (y - 3)^2 - 9 - 13 = 0. \][/tex]

Simplify:

[tex]\[ (x + 2)^2 + (y - 3)^2 - 26 = 0, \][/tex]

[tex]\[ (x + 2)^2 + (y - 3)^2 = 26. \][/tex]

This represents a circle centered at [tex]\( (-2, 3) \)[/tex] with a radius of [tex]\( \sqrt{26} \)[/tex].

2. Find the Gradient of the Tangent Line:

The gradient of the tangent line at a point on a circle is perpendicular to the radius at that point. The gradient of the radius (from the center to the point [tex]\( (3, 4) \)[/tex]) can be found as follows:

The center of the circle is [tex]\( (-2, 3) \)[/tex], and the point of tangency is [tex]\( (3, 4) \)[/tex].

The gradient (slope) of the radius [tex]\( m_{\text{radius}} \)[/tex] is:

[tex]\[ m_{\text{radius}} = \frac{4 - 3}{3 - (-2)} = \frac{1}{5}. \][/tex]

Since the tangent is perpendicular to the radius, the gradient [tex]\( m_{\text{tangent}} \)[/tex] is:

[tex]\[ m_{\text{tangent}} = -\frac{1}{m_{\text{radius}}} = -5. \][/tex]

3. Write the Equation of the Tangent Line:

Using the point-slope form of the line equation [tex]\( y - y_1 = m(x - x_1) \)[/tex] with [tex]\( m = -5 \)[/tex] and the point [tex]\( (3, 4) \)[/tex]:

[tex]\[ y - 4 = -5(x - 3), \][/tex]

[tex]\[ y - 4 = -5x + 15, \][/tex]

[tex]\[ y = -5x + 19. \][/tex]

To write the equation in standard form [tex]\( Ax + By + C = 0 \)[/tex]:

[tex]\[ 5x + y - 19 = 0. \][/tex]

Simplify:

[tex]\[ 5x + y = 19. \][/tex]

4. Match with the Given Options:

We see that this matches the option (c):

c. [tex]\( 5x + y = 19 \)[/tex].

So, the correct answer is:
c. [tex]\( 5x + y = 19 \)[/tex].
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